Question

This is validate.py

import cgi
import yate
import sqlite3


connection = sqlite3.connect('users.sqlite')
cursor = connection.cursor()

print(yate.start_response('text/plain'))
form=cgi.FieldStorage()
for each_form_item in form.keys():
  if (each_form_item=='username'):
    username=form[each_form_item].value
  if (each_form_item=='password'):
    password=form[each_form_item].value

result=cursor.execute('SELECT USERNAME from validate')
usernames=[row[0] for row in result.fetchall()]
for each_username in usernames:
    if (username==each_username):
        pass_result=cursor.execute('SELECT PASSWORD from validate where username=?',(each_username,))
    password1=[row[0] for row in pass_result.fetchall()]
    for each_password in password1:
        if (each_password==password):
            print('Login Success')
           #Here want to run another python program eg welcome.py
        else:
            print('Login Failure')

Web服务器在后台运行。如果上面代码中的条件为真，我想将网页重定向到另一个python程序。我怎么做？

编辑：

的index.html

<html>
<head>
 <title>Login Page</title>
 <link type="text/css" rel="stylesheet" href="coach.css" />
  </head>
  <body>
  <img src="images/logo-cel-transparent_0.png" width="74" height="64">      <strong><img src="images/logo-cel-transparent_0.png"  alt="Cel logo" width="74" height="64" align="right">
     </strong>
     <h1 align="center"><strong>Central Electronics Limited</strong></h1>
    <p>&nbsp;</p>
      <h2 align="center">Storage Management System</h2>
    <p>&nbsp;</p>
       <p align="center">Login to System</p>
     <p align="center">&nbsp;</p>
     <form action="/cgi-bin/validate.py" method="post">
    <div align="center">User name :
     <input type="text" name="username" value=""> <br>
       Password : <input type="text" name="password" value="">  <br>
     <input name="Submit" type="submit" value="Submit">
     </div>
     </form>
     </body>
     </html>

当我点击提交按钮时，validate.py会运行。现在，如果用户名和密码匹配，我希望Web浏览器自动将浏览器重定向到另一个py文件或html页面，而无需用户做任何事情。

EDIT2：

我正在使用代码为：

的python服务器

  from http.server import HTTPServer, CGIHTTPRequestHandler

  port = 8080

   httpd = HTTPServer(('', port), CGIHTTPRequestHandler)
   print("Starting simple_httpd on port: " + str(httpd.server_port))
   httpd.serve_forever()

这是使用命令提示符运行的。然后使用＆＃34; localhost：8080＆＃34;。

在Web浏览器中打开索引页面

Answer 1

您是否尝试过Python subprocesses?

Answer 2

以这种方式使用execfile命令：

for each_username in usernames:
    if (username==each_username):
        pass_result=cursor.execute('SELECT PASSWORD from validate where username=?',(each_username,))
    password1=[row[0] for row in pass_result.fetchall()]
    for each_password in password1:
        if (each_password==password):
            print('Login Success')
            execfile(PATH_TO_THE_FILE+"./welcome.py")
        else:
            print('Login Failure')

注意：PATH_TO_THE_FILE是磁盘中的路径，它应该是一个字符串

修改

当您使用python 3x时，这里是execfile命令的替代方法：

with open("welcome.py") as f: code = compile(f.read(), "welcome.py", 'exec') exec(code)

Answer 3

您可以在其他Python文件中创建一个以页面为参数的方法，而不是生成子流程。然后，您可以将该方法导入到已发布的文件中。

在您要调用的文件中＆＃34; file.py＆＃34;：

def start(page):
    do_something()

现在：

from file import start

for each_username in usernames:
    if (username==each_username):
        pass_result=cursor.execute('SELECT PASSWORD from validate where username=?',(each_username,))
password1=[row[0] for row in pass_result.fetchall()]
for each_password in password1:
    if (each_password==password):
        print('Login Success')
       start(some_page)
    else:
        print('Login Failure')

Answer 4

因此，您似乎希望从CGI脚本内部重定向用户以处理POST请求。好吧，为此，请设置Location标题。您似乎正在使用库来打印所有标题，但您需要更改它。

正如here所示，这看起来像这样：

import cgi
import yate
import sqlite3


connection = sqlite3.connect('users.sqlite')
cursor = connection.cursor()



form=cgi.FieldStorage()
for each_form_item in form.keys():
  if (each_form_item=='username'):
    username=form[each_form_item].value
  if (each_form_item=='password'):
    password=form[each_form_item].value

result=cursor.execute('SELECT USERNAME from validate')
usernames=[row[0] for row in result.fetchall()]
for each_username in usernames:
    if (username==each_username):
        pass_result=cursor.execute('SELECT PASSWORD from validate where username=?',(each_username,))
    password1=[row[0] for row in pass_result.fetchall()]
    for each_password in password1:
        if (each_password==password):
            print('Location:your/new/url')
        else:
            print('Content-type:text/plain')
            print('')
            print('Login Failure')

如何在满足某些条件时执行另一个python程序？

4 个答案: