Question

我对新的YouTube API有疑问。通过ajax调用版本2我可以将最后一个视频上传到播放列表，我该如何处理新的API？谢谢你的支持。

编辑

感谢您的回答，我尝试了代码，但返回了一个javascript错误：“无法在html代码下方读取属性'setApiKey'未定义”：

<!doctype html>
<html>
  <head>
    <title>YouTube</title>
  </head>
  <body>    
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
    <script src="https://apis.google.com/js/client.js?onload=handleClientLoad"></script>

    <script>    
        gapi.client.setApiKey('{API-KEY-HERE}');
        gapi.client.load('youtube', 'v3', function () {

            var request = gapi.client.youtube.playlistItems.list({
                part: 'snippet',
                playlistId: 'PLTK1i0pncVu_tLhgrPo_o7QcRocqozxUv'
            });

            request.execute(function (response) {
                response.items.sort(function(a,b) {return a.snippet.publishedAt < b.snippet.publishedAt})

                for (var i=0; i<response.items.length;i++)
                {
                    console.log(response.items[i].snippet.title + " published at " + response.items[i].snippet.publishedAt)
                }
            });
        });
    </script>   


  </body>
</html>

Answer 1

这样的内容会加载指定播放列表的所有视频，并按publishedAt排序。对于最新的视频，只需获得第一个结果。

<!doctype html>
<html>
<head>
    <title>YouTube</title>
</head>

<body>

    <script>
        var allVideos = new Array();

        function onGoogleLoad() {
            gapi.client.setApiKey('{YOUR-API-KEY}');
            gapi.client.load('youtube', 'v3', function() {

                GatherVideos("", function() {

                    allVideos.sort(function(a, b) {
                        return Date.parse(b.snippet.publishedAt) - Date.parse(a.snippet.publishedAt);
                    })

                    for (var i = 0; i < allVideos.length; i++) {
                        console.log(allVideos[i].snippet.title + " published at " + allVideos[i].snippet.publishedAt)
                    }
                });
            });
        }

        function GatherVideos(pageToken, finished) {
            var request = gapi.client.youtube.playlistItems.list({
                part: 'snippet',
                playlistId: 'PLTK1i0pncVu_tLhgrPo_o7QcRocqozxUv',
                maxResults: 50,
                pageToken: pageToken
            });

            request.execute(function(response) {
                allVideos = allVideos.concat(response.items);
                if (!response.nextPageToken)
                    finished();
                else
                    GatherVideos(response.nextPageToken, finished);
            });
        }
    </script>

    <script src="https://apis.google.com/js/client.js?onload=onGoogleLoad"></script>

</body>

</html>

YouTube API v3会从播放列表中加载最后一个视频

1 个答案: