Question

好的，我真的花了两天时间，这让我很难过。

在我的主UIViewController中，我调用了一个WebViewController，它是一个内部有UIWebView的UIViewController：

UOLCategoriesWebViewController *ucwvcontroller = [[UOLCategoriesWebViewController alloc] initWithNibName:@"UOLCategoriesWebViewController" bundle:nil];

    [self presentModalViewController:ucwvcontroller animated:YES];
    [ucwvcontroller release];

在UOLCategoriesWebViewController中我调用了委托方法shouldStartLoadWithRequest，当用户点击特定类型的链接时，它解析了params并返回到主UIViewController（或者至少这就是我想要的东西）做）：

- (BOOL)webView:(UIWebView*)webView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType {
    BOOL continueOrExit = YES;
    NSURL *url = request.URL;
    NSString *urlString = [url relativeString];
    NSString *urlParams = [url query];
    NSArray *urlParamArr = [urlParams componentsSeparatedByString:@"&"];
    NSLog(@"the url is: %@",urlString);
    //NSLog(@"the params are: %@,%@",[urlParamArr objectAtIndex:0],[urlParamArr objectAtIndex:1]);

    //BOOL endTrain1 = [[urlParamArr objectAtIndex:1] hasPrefix:@"subCatValue"];
    //BOOL endTrain2 = ([urlParamArr objectAtIndex:1
    //NSLog(@"Number of elements: %@",[urlParamArr count]);
    if (navigationType == UIWebViewNavigationTypeLinkClicked)
    {
        //NSLog(@"Enter into His glory");

        if ([urlString hasSuffix:@"categories_list.php"]) {

            //NSLog(@"2nd Heaven");
            continueOrExit = YES;

        }else if ([[urlParamArr objectAtIndex:1] hasPrefix:@"subCatValue"]) {
            continueOrExit = NO;
            NSLog(@"end of the train");
            NSArray *firstParamStringArr = [[urlParamArr objectAtIndex:0] componentsSeparatedByString:@"="];
            NSArray *secondParamStringArr = [[urlParamArr objectAtIndex:1] componentsSeparatedByString:@"="];
            NSString *catSelected = [firstParamStringArr objectAtIndex:1];
            NSString *subCatSelected = [secondParamStringArr objectAtIndex:1];



            //go back to native app
            [self goBackToMain:catSelected andSubCat:subCatSelected];



        }
    }
    return continueOrExit;
}

实际上在我调用goBackToMain方法的上述函数中，我希望它调用委托方法并返回到mainviewcontroller。不幸的是，在执行goBackToMain方法后，它返回到此方法并继续返回continueOrExit。

无论如何都要让它真正退出而不返回任何东西？我尝试过多次退货但无济于事。或者我可以在html页面中传递一些javascript直接调用此方法，这样我就不必通过这个委托方法了吗？

提前感谢您的帮助！

Answer 1

您可以尝试在委托方法执行后推迟goBackToMain:andSubCat:的调用。这样，委托方法可以返回，然后处理调用：

NSArray *firstParamStringArr = [[urlParamArr objectAtIndex:0] componentsSeparatedByString:@"="];
NSArray *secondParamStringArr = [[urlParamArr objectAtIndex:1] componentsSeparatedByString:@"="];
NSString *catSelected = [firstParamStringArr objectAtIndex:1];
NSString *subCatSelected = [secondParamStringArr objectAtIndex:1];

NSMethodSignature *sig = [self methodSignatureForSelector:@selector(goBackToMain:andSubCat:)];
NSInvocation *inv = [NSInvocation invocationWithMethodSignature:sig];
[inv retainArguments];
[inv setTarget:self];
[inv setSelector:selector];
[inv setArgument:&catSelected atIndex:2];
[inv setArgument:&subCatSelected atIndex:3];
[inv performSelector:@selector(invoke) withObject:nil afterDelay:0.0];

解雇uiwebview

1 个答案: