两个概率具有相同的代码,但是当我想要添加时,文本"输入第一个数字"没有显示。我做错了什么?
import java.util.Scanner;
public class berketurer {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int command1;
int number1;
int number2;
int result;
System.out.print("for subtraction,press 1.for addition,press 2.");
command1=input.nextInt();
if (command1==1)
System.out.print("enter the first number:");
number1=input.nextInt();
System.out.print("enter the second number:");
number2=input.nextInt();
result=number1-number2;
System.out.printf("the result is=%d\n",result);
if (command1==2)
System.out.print("enter the first number;"); //here is the problem
number1=input.nextInt();
System.out.print("enter the second number;");
number2=input.nextInt();
result=number1+number2;
System.out.printf("the result is=%d\n",result);
}
}
答案 0 :(得分:3)
你错过了if语句体中的{}
大括号,你所拥有的只是缩进(由于Java不是Python,它不起作用)。
答案 1 :(得分:0)
import java.util.Scanner;
public class berketurer {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int command1;
int number1;
int number2;
int result;
System.out.print("for addition,press 1.for subtraction,press 2.");
command1=input.nextInt();
if (command1==1) { // <-- opening
System.out.print("enter the first number:");
number1=input.nextInt(); // <- your code stops here
System.out.print("enter the second number:");
number2=input.nextInt();
result=number1-number2;
System.out.printf("the result is=%d\n",result);
} // <-- closing
if (command1==2) { // <-- opening
System.out.print("enter the first number;"); //here is the problem
number1=input.nextInt();
System.out.print("enter the second number;");
number2=input.nextInt();
result=number1+number2;
System.out.printf("the result is=%d\n",result);
} // <-- closing
}
}
你忘记了每个街区的开启和关闭。因此,第一次打印不会执行,您的代码会停止等待输入。