我创建了一个名为“questions”的数组,其中包含结构“QuizQuestion”的实例 - 基本上我希望“nextQuestion”函数从结构数组(问题)中提取下一个问题并将其显示给用户(我了解如何通过标签等呈现数据,我只是不知道如何访问它)。
我试过调用数组索引然后调用实例,但这似乎不起作用。我还尝试创建一个“QuizQuestion”实例作为变量,并在“NextQuestion”函数中使用它,但是我不知道如何自动从“问题”中提取问题。
由于
import UIKit
class ViewController: UIViewController {
@IBOutlet weak var questionLabel: UILabel!
@IBOutlet weak var answerLabel: UILabel!
@IBOutlet weak var explanationLabel: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
questionVariable()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
struct QuizQuestion {
let question: String
let answer: Bool
let explanation: String
}
let questions: [QuizQuestion] = [
QuizQuestion(question: "Red is a four letter word", answer: false, explanation: "Red is not a four letter word"),
QuizQuestion(question: "Dog is a three letter word", answer: true, explanation: "Dog is most likely a three letter word"),
QuizQuestion(question: "Cow is a three letter word", answer: true, explanation: "Cow is most likely a three letter word")
]
var nextQuestion = QuizQuestion.self[1]
func questionVariable() {
if nextQuestion.answer == true {
questionLabel.text = nextQuestion.question
explanationLabel.text = nextQuestion.explanation
answerLabel.text = "Correct"
}
}
}
答案 0 :(得分:1)
你可以定义一个嵌套函数(Swift中最简单的闭包形式),如下所示:
let nextQuestion = getNextQuestion()
var question_1 = nextQuestion(0)
var question_2 = nextQuestion(1)
var question_3 = nextQuestion(2)
println("1.question text: \(question_1.question)")
println("2.question text: \(question_2.question)")
println("3.question text: \(question_3.question)")
然后您可以访问下面的问题列表
{{1}}
答案 1 :(得分:0)
从数组中检索问题的简单函数。声明一个实例变量来保存当前索引。
var currentIndex = 0
func nextQuestion() -> QuizQuestion {
// initialize current question
var currentQuestion: QuizQuestion = QuizQuestion(question: "", answer: false, explanation: "")
if currentIndex < questions.count {
currentQuestion = questions[currentIndex]
}
currentIndex++
return currentQuestion
}