Question

我有一个名为Receipt的自定义类。它具有另一个名为Retailer的类的属性。 Retailer有另一个名为retailerName的属性。

我得到了一组Receipt个对象。我希望它被排序为NSDictionary，其键将是字母，值将是Receipt的数组Retailer对象的retailerName以字母开头并且数组按字母顺序排序。

我有什么：

[
  {
    "retailerName": "Adidas",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Book My Show",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Albert-Heijn",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Amazon",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "BlackBerry",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Lambhorgini",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Lewis Outlet",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Boston Store",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  },
  {
    "retailerName": "Lidl",
    "totalCost": 392.1,
    "purchasedOn": 1461218024549
  }
]

我需要的是什么：

{
    "A": [
          {
              "retailerName": "Adidas",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          },
          {
              "retailerName": "Albert-Heijn",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          },
          {
              "retailerName": "Amazon",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          }
          ],
    "B": [
          {
              "retailerName": "BlackBerry",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          },
          {
              "retailerName": "Book My Show",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          },
          {
              "retailerName": "Boston Store",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          }
          ],
    "L": [
          {
              "retailerName": "Lambhorgini",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          },
          {
              "retailerName": "Lewis Outlet",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          },
          {
              "retailerName": "Lidl",
              "totalCost": 392.1,
              "purchasedOn": 1461218024549
          }
          ]
}

我知道这种情况并不复杂，但我尽力解释。如果需要，请询问进一步的解释。

提前致谢。

Answer 1

我解决了我的问题：

这是我做的：

@implementation NSMutableDictionary (DictionaryForSectionIndex)

+(NSMutableDictionary *)createDictionaryForSectionIndex:(NSArray *)array
{
    NSMutableDictionary *dict = [NSMutableDictionary dictionary];
    for (char firstChar = 'a'; firstChar <= 'z'; firstChar++)
    {
        //NSPredicates are fast
        NSString *firstCharacter = [NSString stringWithFormat:@"%c", firstChar];
        NSArray *content = [array filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"retailerName beginswith[cd] %@", firstCharacter]];
        NSMutableArray *mutableContent = [NSMutableArray arrayWithArray:content];

        if ([mutableContent count] > 0)
        {
            NSString *key = [firstCharacter uppercaseString];
            [dict setObject:mutableContent forKey:key];
        }
    }
    return dict;
}

@end

Answer 2

Array = [Array
     sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2)
                          {
                              NSNumber *number1 = [NSNumber
                              numberWithFloat:[someValue floatValue]];
                             NSNumber *number2 = [NSNumber
                              numberWithFloat:[[somevalue floatValue]];

                              return [number2 compare:number1];
                        }];

您可以选择字典中的特定键并尝试对其进行排序

如何将NSArray对象排序为字母NSDictionary？

2 个答案: