Question

我需要插入数据。对于浮点数，我通常使用

interp1(given_time,given_data,uniform_time)

但是，在这种情况下，我的given_data是一个字符串数组：

time=[1,5,18,30,40,42,47,54,64]

season=[{'winter'},{'winter'},{'winter'}, {'spring'}, {'spring'}, {'spring'}, {'summer'}, {'summer'}, {'summer'} ]

uniform_time=1:5:64

uniform_season= ????

输出的每个单元格必须是根据最近值uniform_time

的字符串

如何在matlab中实现它？

如果uniform_time(i)恰好位于time(j)和time(k)之间，则season(j)或season(k)的值均可接受。

在上面的案例中，我希望得到：

uniform_season= [{'winter'}, {'winter'}, {'winter'}, {'winter'}, {'winter'}, {'spring'}, {'spring'}, {'spring'}, {'spring/summer'}, {'summer'}, {'summer'}, {'summer'}, {'summer'}]

{'spring/summer'}我的意思是{'spring'}或{'summer'}，但不是两者都是{'spring/summer'}。

我根据这张表计算了它：

new data: 1 6   11  16  21  26  31  36  41  46  51  56  61
closest old data: 1 5   18  18  18  30  30  40  41/42   47  54  54  64
string of old data: 'winter'    'winter'    'winter'    'winter'    'winter'    'spring'    'spring'    'spring'    spring/summer'  'summer'    'summer'    'summer'    'summer'

Answer 1

尝试以下方法：

%// Inputs:
time=[1,5,18,30,40,42,47,54,64]
season=[{'winter'},{'winter'},{'winter'}, {'spring'}, {'spring'}, {'spring'}, {'summer'}, {'summer'}, {'summer'} ]
uniform_time=1:5:64

%// Change season to an ordinal list
[season_unique,~,season_int] = unique(season, 'stable')
idx = interp1(time, season_int, uniform_time, 'nearest-neighbour') %// Good chance you'll want to add the 'extrap' flag here as well
season_unique(idx)

如何在分类数据上进行插值

1 个答案: