MySQL插入select

时间:2015-06-05 02:00:04

标签: mysql insert-select

我试图在表中插入一行,该表有3个外键。为了获得这些钥匙我有独特的" filds搜索。

SQL

create table user(
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    name VARCHAR(30) NOT NULL,
    username VARCHAR(50) NOT NULL,
    password VARCHAR(30) NOT NULL,
    access_token VARCHAR(32),
    reg_date TIMESTAMP,
    UNIQUE(username),
    UNIQUE(access_token)


);

create table pharmacy(
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    places_id VARCHAR(50) NOT NULL,
    name VARCHAR(30) NOT NULL,
    coord VARCHAR(50) NOT NULL,
    description VARCHAR(100),
    reg_date TIMESTAMP,
    UNIQUE(places_id)
);

create table item(
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    name VARCHAR(30) NOT NULL,
    description VARCHAR(100),
    reg_date TIMESTAMP,
    UNIQUE(name)
);

create table item_bought(
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    id_user INT(6) UNSIGNED,
    id_pharmacy INT(6) UNSIGNED,
    id_item INT(6) UNSIGNED,
    price float(6,2) NOT NULL,
    bought_date date,
    reg_date TIMESTAMP,

    foreign key(id_user)    
       references user(id),

    foreign key(id_pharmacy)
       references pharmacy(id),

    foreign key(id_item)
       references item(id)
);

我在JAVA中构建的查询:

INSERT INTO item_bought (id_user, id_pharmacy, id_item, price, bought_date)
     SELECT user.id, pharmacy.id, item.id, 12.32, date('1999-02-24') 
     FROM user, pharmacy, item
     WHERE ( SELECT user.id, user.username, pharmacy.id,
   pharmacy.places_id, item.id, item.name 
         FROM item, pharmacy, item 
         WHERE user.username='jhon', pharmacy.places_id='id1', item.name='ibuprufen' )

这是我得到的错误:

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Not unique table/alias: 'item'

感谢您的帮助:D

解决方案

根据Gordon Linoff的回答:

INSERT INTO item_bought (id_user, id_pharmacy, id_item, price, bought_date)
     SELECT (SELECT u.id FROM user u WHERE u.username = 'jhon'),
            (SELECT p.id FROM pharmacy p WHERE p.places_id = 'id1'),
            (SELECT i.id FROM item i WHERE i.name='ibuprufen'),
            (SELECT 13.22), (SELECT date('1999-02-12'));

更优雅!

3 个答案:

答案 0 :(得分:1)

问题似乎是这一行:

FROM item, pharmacy, item

你有item两次。尝试删除一个。

答案 1 :(得分:1)

在您的代码中,您在同一查询中对同一个表调用两次。这是错误的。它应该是:

INSERT INTO item_bought (id_user, id_pharmacy, id_item, price, bought_date)
     SELECT user.id, pharmacy.id, item.id, 12.32, date('1999-02-24') 
     FROM user, pharmacy, item
     WHERE ( SELECT user.id, user.username, pharmacy.id,
   pharmacy.places_id, item.id, item.name 
         FROM item, pharmacy
         WHERE user.username='jhon', pharmacy.places_id='id1', item.name='ibuprufen' )

答案 2 :(得分:1)

我认为您想要的查询是:

INSERT INTO item_bought (id_user, id_pharmacy, id_item, price, bought_date)
     SELECT (SELECT u.id FROM user u WHERE u.username = 'jhon'),
            (SELECT p.id FROM pharmacy p WHERE p.places_id = 'id1'),
            (SELECT i.id FROM item i WHERE i.name='ibuprufen');

您的查询有很多错误 - 相同的表在from中没有表别名,where子句中的逗号,标量上下文中的select返回多列和(可能)多行而不是一行。另外,在where子句中使用逗号是非常糟糕的做法。