Lua期望=在elseif附近

时间:2015-06-04 21:51:20

标签: lua

我在尝试运行一个elseif时遇到一个错误,要求我在其他地方放置= =但是我之前使用过相同的方法,并且没有问题被返回。

if ((GAMEPLAY.GET_DISTANCE_BETWEEN_COORDS( -629.99, -236.542, 38.05 , location.x, location.y, location.z, true ) < 2 ))  then
        setMessage("Press E to start the heist.")
        --SelectPart(1) --start
        heistP[1]
    elseif ((startH == true) and (jewelPart == false) and (escape == false) and (dropoffP == false)) then

        heistP[2]
        --SelectPart(2) --loadBlips
    elseif ((jewelPart == true) and (escape == false) and (dropoffP == false)) then
        --SelectPart(3) -- Jewels
    elseif ((escape == true) and (dropoffP == false)) then
        setMessage("Escape the cops!")
        --SelectPart(4) --EscapeC
    elseif (dropoffP == true) then
        --SelectPart(5) --DropOff
    end

heistP = {
  [1] = function()
    local playerPed = PLAYER.PLAYER_PED_ID()
    local location = ENTITY.GET_ENTITY_COORDS(playerPed, nil)
    if(get_key_pressed(Keys.E))then
        PLAYER.SET_PLAYER_WANTED_LEVEL(PLAYER.GET_PLAYER_PED(playerPed),3,false)
        --PLAYER.SET_PLAYER_WANTED_LEVEL_NOW(PLAYER.GET_PLAYER_PED(playerPed),false)
        PED.SET_PED_COMPONENT_VARIATION(playerPed, 9, 1, 0, 0)
        startH = true
    end
end,

}

1 个答案:

答案 0 :(得分:1)

heistP[1]heistP[2]应为heistP[1]()heistP[2]()。我假设heistP[2]()被定义在其他地方,如果没有,你需要定义它。