是否可以在AutoHotkey中定位变量中的特定字符?在这种情况下,我希望变量中的第一个字符大写/小写。
let paragraphStyle = NSMutableParagraphStyle()
paragraphStyle.alignment = NSTextAlignment.Center
paragraphStyle.lineHeightMultiple = 0.75
var attrString = NSMutableAttributedString(string: value)
attrString.addAttribute(NSParagraphStyleAttributeName, value:paragraphStyle, range:NSMakeRange(0, attrString.length))
// showLabel.clipsToBounds = false // has no effect
showLabel.attributedText = attrString
// showLabel.sizeToFit() // also appears to have no effect
答案 0 :(得分:2)
在您的情况下,StringUpper会执行:
stringUpper, foo, foo, T
T
代表:
该字符串将转换为标题大小写。例如,“GONE with the WIND”将成为“Gone With the Wind”。 “
除此之外,您始终可以使用StringTrimRight/Left或SubStr()确定子字符串,更改它们并在之后附加它们:
firstLetter := subStr(foo, 1, 1)
stringUpper, firstLetter, firstLetter
remainingLetters := subStr(foo, 2, strLen(foo))
foo := firstLetter . remainingLetters
; or, equally:
; foo = %firstLetter%%remainingLetters%
答案 1 :(得分:2)
@ Blauhirn解决方案的替代方案:
MsgBox % foo := Format("{:U}", SubStr(foo, 1,1)) . subStr(foo, 2, strLen(foo))
这也可以在RegEx中完成。
::::::被修改::::::::::
这是一个完整的示例,它使用连接已删除......
fu := "fu"
bar := "beyond all recognition!"
MsgBox % capitalize(fu) A_space capitalize(bar)
Return
capitalize(x) {
return Format("{:U}", SubStr(x, 1,1)) subStr(x, 2, strLen(x))
}
正则表达式:
;This is the only example that accounts for Whitespace
var := " regex is cool!"
MsgBox % RegExReplace(var, "^(\s*)(.)", "$1$u2")
NumPut / DllCall:
var := "autohotkey is awesome!"
NumPut(Asc(DllCall("CharUpperA", Str,Chr(NumGet( var,0,"UChar")),Str)), var,0,"UChar")
MsgBox % var