Question

我在文本文件中放了一个列表。我希望python读取文本文件并将内容作为列表返回。但是，它是以字符串形式读取内容：

文字档案：

['a','b','c']

的Python：

ids=[]

writtenFile =open('file.txt')
readFile=writtenFile.read()
ids= readFile
writtenFile.close()
print ids

返回的内容是[＆＃39; a＆＃39;＆＃39; b＆＃39;＆＃39; c＆＃39;]作为字符串，而不是列表或文本。有没有办法可以从文本文件中检索[＆＃39; a＆＃39;＆＃39;＆＃39;＆＃39; c＆＃39;]然后将其存储在ids字符串中以便ids是一个列表[＆＃39; a＆＃39;＆＃39; b＆＃39;＆＃39; c＆＃39;]而不是字符串？＆＃34; [＆＃39;一个＆＃39;＆＃39; B＆＃39;＆＃39; C＆＃39;]＆＃34;

Answer 1

使用ast.literal_eval逐字地评估文件的内容，因为它写的实际上是一个字符串：

data = ast.literal_eval(open('data.txt').read()) # create file, read contents, evaluate

Answer 2

如果你只是采用相同的格式，那么剥离和拆分的最快方式就是：

org 100h

;mov ah,0ah
;mov dx,offset place
;int 21h             ; getting the place(directory) of the file   

;ADD 0 TO END OF STRING <==================================

;mov si,offset place
;inc si
;mov dl,[si]         ;<== LENGTH OF STRING IS BYTE, NOT WORD
;mov dh,0            ;<================== CLEAR DH TO USE DX
;inc dx
;add si,dx           ;<========= SI POINTS TO FINAL CHAR + 1
;mov [byte ptr si],0 ;<========= THE NUMBER ZERO HAS NO SIZE 

;LINE BREAK.

;;mov ah,02
;mov dl,13
;int 21h
;mov ah,02
;mov dl,10
;int 21h

mov ah,0ah
mov dx,offset filename
int 21h            ;getting the file name 

;ADD 0 TO END OF STRING <==================================

mov si,offset filename
inc si
mov dl,[si]         ;<== LENGTH OF STRING IS BYTE, NOT WORD
mov dh,0            ;<================== CLEAR DH TO USE DX
inc dx
add si,dx           ;<========= SI POINTS TO FINAL CHAR + 1
mov [byte ptr si],0 ;<========= THE NUMBER ZERO HAS NO SIZE 

;LINE BREAK.

mov ah,02
mov dl,13
int 21h
mov ah,02
mov dl,10
int 21h


;call gotoplace     ;go to the place of the file
;------------------

call openfile      ;open the file 
;------------------

mov ah,3fh
mov si,offset filehandle
mov bx,[si]              ;move file adress to bx
mov cx,40000             ;numbers of bytes to read
mov dx,offset buff       ;pointer to read buffer
int 21h 

mov si,offset filesize   ;move si pointer to filesize
mov [si],ax              ;move to filesize how many bytes read 
;------------------       

;writing on the screen -> 
mov bx,offset buff   ;move bx pointer of buffer
mov si,offset filesize
mov cx,[si]          ;move cx how many to write

startwrite:

mov ah,2
mov dl,[bx] ;move dl letter in place [bx]
int 21h

inc bx
dec cx
jnz startwrite

;WAIT UNTIL USER PRESS ANY KEY  <===========================
  mov  ah,7
  int  21h

;FINISH PROGRAM  <==========================================
  mov  ax, 4c00h
  int  21h           


proc gotoplace
    mov ah,3bh
    mov dx,offset place ;move offset place to dx
    add dx,2
    int 21h

    ret

endp gotoplace    

proc openfile

    mov ah,3dH
    mov al,2  ;open for read / write
    mov dx,offset filename  ;move dx offset filename 
    add dx,2
    int 21h   
    ;--------------------------

    mov si,offset filehandle ;move offset filehandle(location in the memory) to si
    mov [si],ax              ;move the file adress to the 'filehandle'(location in the meory' 

    ret

endp openfile

ret

filehandle dd ?
filename db 40
         db 42 dup (0) 
place db 40
      db 42 dup (0) 

      buff db 40000 dup (0)

filesize dw ?  ;<========= IN 8086 WE CANNOT READ MORE THAN 64KB.

Python：以列表作为列表读取文件

2 个答案: