Question

这是我的代码：

First_xor_list=[0xaa,0x89,0xc4,0xfe,0x46]
Secpnd_xor_list=[0x78,0xf0,0xd0,0x03,0xe7]
after_xor=[]
xor_helper=[]
name = "UserNa"

after_xor.append(hex(ord(name[0])))#first stage - xor from second char to    end and add the second char to the end of  the list
for i in range(len(name)):
    if i < len(name)-1:
        after_xor.append(hex((First_xor_list[i])^ (ord(name[i+1]))))
    elif i < len(name):
        after_xor.append(hex(ord(name[1])))

问题是这些值作为String进入列表，这是输出：

['0x55', '0xd9', '0xec', '0xb6', '0xb0', '0x27', '0x73']

因为我必须对列表中的值进行XOR，我需要这样：

[0x55, 0xd9, 0xec, 0xb6, 0xb0, 0x27, 0x73]

如何以这种方式将它们添加到列表中？

Answer 1

删除hex，hex只将int转换为包含其十六进制形式的字符串。

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Answer 2

函数hex以十六进制为基础将数字转换为字符串。要进行计算，只需将hex保留，并将元素保留为数字：

after_xor.append(ord(name[0])) # first stage - xor from second char to    end and add the second char to the end of  the list
for x, ch in zip(First_xor_list, name[1:]):
    after_xor.append(x^ord(ch))
after_xor.append(ord(name[1]))

如何在保留原始形式的同时添加到列表HEX值

2 个答案: