Question

我有一个名为DailySales的表（ID int，Date date，Time Time，CashSale Money，CardSale money，TotalSale money）。现在我想低于结果......

                  Date : 04-06-2015

                  Time : 09:01 - 10:00
CashSale           CardSale                   TotalSale
10000.00           15000.00                   25000.00

                 Time : 10:01 - 11:00
CashSale           CardSale                   TotalSale
20000.00           15000.00                   35000.00
.
.
.

请帮帮我，感谢..

Answer 1

我建议您最好将日期/时间存储在datetime或datetime2列中，而不是仅存储时间，然后使用可以使用{{1获取时间的函数。

假设datepart列实际上是Time，您可以执行以下操作：

DateTime

这会在一小时一小时（例如09:00:00至09：59：59,10：00至10:59:59等）将其分开。如果您想要偏移分割的位置，例如在一小时后的1分钟，则可以使用SELECT Date, datepart(Hour, Time) AS Hour, sum(CashSale) AS ByCash, sum(CardSale) AS ByCard, sum(TotalSale) AS NetSale FROM DailySales GROUP BY Date, datepart(Hour, Time)函数，例如dateadd代替dateadd(minute, -1, Time)。< / p>

如果您以某种其他方式存储字符串，例如作为字符串，那么您希望根据该字符串表达式对字符串进行分组，例如Time

Answer 2

这只是一个如何实现这一目标的提示。这只是sql可以为您做的最大值。其余的应该在报告中完成：

准备数据：

DECLARE @t TABLE
    (
      Date DATE ,
      Time TIME ,
      CashSale MONEY ,
      CardSale MONEY ,
      TotalSale MONEY
    )

INSERT  INTO @t
VALUES  ( '20150603', '09:30', 10, 5, 15 ),
        ( '20150604', '09:02', 10, 5, 15 ),
        ( '20150604', '09:30', 10, 5, 15 ),
        ( '20150604', '10:00', 10, 5, 15 ),
        ( '20150604', '11:01', 10, 5, 15 ),
        ( '20150604', '11:30', 10, 5, 15 ),
        ( '20150604', '12:30', 10, 5, 15 );

查询：

WITH times
AS ( SELECT   *
     FROM ( VALUES
          ( CAST('09:01' AS TIME), CAST('10:00' AS TIME)),
          ( CAST('10:01' AS TIME), CAST('11:00' AS TIME)),
          ( CAST('11:01' AS TIME), CAST('12:00' AS TIME)) ) times ( StartTime, EndTime )
             )
    SELECT  *
    FROM    ( SELECT    t.Date ,
                        ti.StartTime ,
                        ti.EndTime ,
                        SUM(CashSale) CashSale ,
                        SUM(CardSale) CardSale ,
                        SUM(TotalSale) TotalSale
              FROM      @t t
                        JOIN times ti ON t.Time BETWEEN ti.StartTime AND ti.EndTime
              WHERE     Date = '20150604'
              GROUP BY  t.Date ,
                        ti.StartTime ,
                        ti.EndTime
            ) t UNPIVOT( Amount FOR SaleType IN ( [CashSale], [CardSale], [TotalSale] ) ) u
    ORDER BY Date ,
            StartTime ,
            EndTime ,
            CASE SaleType
              WHEN 'TotalSale' THEN 1
              WHEN 'CashSale' THEN 2
              WHEN 'CardSale' THEN 3
            END

输出：

Date        StartTime           EndTime             Amount  SaleType
2015-06-04  09:01:00.0000000    10:00:00.0000000    45.00   TotalSale
2015-06-04  09:01:00.0000000    10:00:00.0000000    30.00   CashSale
2015-06-04  09:01:00.0000000    10:00:00.0000000    15.00   CardSale
2015-06-04  11:01:00.0000000    12:00:00.0000000    30.00   TotalSale
2015-06-04  11:01:00.0000000    12:00:00.0000000    20.00   CashSale
2015-06-04  11:01:00.0000000    12:00:00.0000000    10.00   CardSale

修改

您可以创建一个表格：

Times(StartTime TIME, EndTime TIME)

在其中插入所有24行：

INSERT INTO Times VALUES ( CAST('09:01' AS TIME), CAST('10:00' AS TIME)), ( CAST('10:01' AS TIME), CAST('11:00' AS TIME)), ( CAST('11:01' AS TIME), CAST('12:00' AS TIME)), .... ( CAST('23:01' AS TIME), CAST('00:00' AS TIME))

你可以使用它：

SELECT * FROM ( SELECT t.Date , ti.StartTime , ti.EndTime , SUM(CashSale) CashSale , SUM(CardSale) CardSale , SUM(TotalSale) TotalSale FROM @t t JOIN Times ti ON t.Time BETWEEN ti.StartTime AND ti.EndTime WHERE Date = '20150604' GROUP BY t.Date , ti.StartTime , ti.EndTime ) t UNPIVOT( Amount FOR SaleType IN ( [CashSale], [CardSale], [TotalSale] ) ) u ORDER BY Date , StartTime , EndTime , CASE SaleType WHEN 'TotalSale' THEN 1 WHEN 'CashSale' THEN 2 WHEN 'CardSale' THEN 3 END

如何在SQL Server中以小时为单位从表中获取记录？

2 个答案: