Question

在this question之后，我想在字符串中包含更多级别的层次结构。例如，这是我的字符串：

sometext
somemore    text here

some  other text

              course: course1

some details
TestName: test1
some other details
Id              Name                marks
____________________________________________________
1               student1            65
2               student2            75
3               MyName              69
4               student4            43

some details
TestName: test3
some other details
Id              Name                marks
____________________________________________________
1               student1            23
3               MyName              63
4               student4            64


              course: course2

some details
TestName: test2
some other details
Id              Name                marks
____________________________________________________
1               student1            84
2               student3            73

some details
TestName: test5
some other details
Id              Name                marks
____________________________________________________
1               MyName              84
2               student2            73


              course: course4

some details
TestName: test1
some other details
Id              Name                marks
____________________________________________________
1               student1            58
2               student3            89

some details
TestName: test2
some other details
Id              Name                marks
____________________________________________________
1               student1            97
3               MyName              60
8               student6            82

我希望了解MyName的详细信息。类似(course1,test1,69),(course1,test3,63),(course2,test5,84),(course4,test2,60)或类似输出的输出。

我无法一步完成，因此得出了这个：

import re
eachcourse = re.split(r'course: \w+',string1)
courselist = re.findall(r'course: (\w+)',string1)
li =[]
for i,course in enumerate(courselist):
    match = re.findall(r".*?TestName: (\w+)(?:(?!\TestName\b).)*MyName\s+(\d+).*?",eachcourse[i+1],re.DOTALL)
    li.append((course,match))
print li

给了我

[('course1', [('test1', '69'), ('test3', '63')]), ('course2', [('test5', '84')]), ('course4', [('test2', '60')])]

有更好更清洁的方式吗？

感谢。

Answer 1

x=re.findall(r"\bcourse: (\w+)(.*?)(?=(?:\bcourse:|$))",x,flags=re.DOTALL)


print [[i[0]]+re.findall(r"TestName: (\w+)(?:(?!\bTestName\b).)*MyName\s*(\d+)",i[1],flags=re.DOTALL) for i in x]

你可以试试这个。虽然格式不完全相同，但它是可用的。

Python：regex findall for subcategories？

1 个答案: