为什么我在打印特定间隔的数字时获得此输出

Question

我试图通过采用特定间隔的开始，结束间隔范围来打印特定间隔之间的数字，但我无法获得正确的输出。

我正在使用Scanner类从用户那里获取输入 我使用了2个区间的start1，start2和end1，end2来显示它们的起始和结束范围。

import java.util.Scanner;
public class Smallest234Number
{
    public static void smallest2NoInterval(int p[],int x[])  
    {
        System.out.println("First interval");

        for(int k=0;k<p.length;k++)
        {
            System.out.println(p[k++]);
        }
        System.out.println("Second Interval");

        for(int k=0;k<x.length;k++)
        {
            System.out.println(x[k++]);
        }
    }

    public static void main(String[] args)
    {
        int ar1[]=new int[10];
        int ar2[]=new int[10];

        int i=0;
        int s=0;

        // i have taken 2 intervals for a base
        System.out.println("Enter the first Interval");
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the first of starting interval");
        int startno1=sc.nextInt();
        //now take input from user startno

        System.out.println("Enter the end of  starting interval");
        int endno1=sc.nextInt();
        //now take input from user endno

        System.out.println("Enter the second interval");
        System.out.println("Enter the first of Second interval");
        int startno2=sc.nextInt();

        //now take input of 2Interval  from user startno1

        System.out.println("Enter the end of Second interval");
        int endno2=sc.nextInt();

        //now take input of 2Interval  from user endno1

        System.out.println("Enter the first interval nos only between start   no and end no");

        System.out.println("Enter the first interval nos only between   start no and end no");

       for(int a=startno1;a<=endno1;a++)
       {
            int inputNo=sc.nextInt();


            if(inputNo<=endno1&&inputNo>=startno1)
            {
                ar1[s]=inputNo;
                s++;
            }
        }
        System.out.println("Enter the Second interval nos only between start no1 and end no1");

       for(int a=startno2;a<=endno2;a++)
       {
            int inputNo=sc.nextInt();


            if(inputNo<=endno1&&inputNo>=startno1)
            {
                ar2[i]=inputNo;
                i++;
             }

        }
        smallest2NoInterval(ar1,ar2);
    }
}

**Output Shown:**

Enter the first Interval
Enter the first of starting interval
1
Enter the end of  starting interval
3
Enter the second interval
Enter the first of Second interval
2
Enter the end of Second interval
4
Enter the first interval nos only between start no and end no
Enter the first interval nos only between start no and end no
1
2
3
Enter the Second interval nos only between start no1 and end no1
2
3
4
First interval
1
3
0
0
0
Second interval
2
0
0
0
0

Answer 1

您在数组i和ar1中使用相同的变量ar2进行索引，这就是为什么您的程序将整数放在ar1中的前两个位置而不是第三位的原因在ar2。在将值放入i=0。

之前，您应使用不同的索引变量或重置ar2

修改 另一个问题是你的打印逻辑

for(int k=0;k<p.length;k++)
{
    System.out.println(p[k++]);
}
System.out.println("Second Interval");

for(int k=0;k<x.length;k++)
{
    System.out.println(x[k++]);
}

你在循环中递增索引变量两次请按照以下方式更正：

for(int k=0;k<p.length;k++)
{
    System.out.println(p[k]);
}
System.out.println("Second Interval");

for(int k=0;k<x.length;k++)
{
    System.out.println(x[k]);
}