我需要根据前一行（从第2位到第13位）的字符串内容和当前行的字符串内容（从第2位到第2位）拆分文本文件（使用.bat命令） 13）...
我解释说：
我的文件看起来像这样：
IA1234567890A XX33 AZE
bla1 XX34 DES
bla2 XX34 DES
bla3 XX34 DES
FA1234567890A XX35 AZE
IA1234567890A XX36 AZE
bla4 XX34 DES
bla5 XX34 DES
bla6 XX34 DES
FA1234567890A XX37 AZE
IB0987654321A XX38 AZE
bla7 XX34 DES
bla8 XX34 DES
bla9 XX34 DES
FB0987654321A XX39 AZE
我希望在以“I”开头的一行的前12个字符（不考虑“I”）与前一行的前12个字符（始终以a开头）分割文件“F”除了第一行，但比较不应该考虑“F”）。
所以我不会在这两行之间拆分文件：
FA1234567890A XX35 AZE
IA1234567890A XX36 AZE
但我会在这两行之间拆分文件：
FA1234567890A XX37 AZE
IB0987654321A XX38 AZE
我知道如何使用分隔符拆分文件，但我完全迷失了这个比较的东西......
如果你们中的一个人能帮我解决这个棘手的问题，我真的很感激......
谢谢！
答案 0 :(得分：1)
此内容来自data.txt并创建output1.txt，output2.txt，... outputn.txt：
@echo off
setlocal enabledelayedexpansion
set outputcount=0
set previousblock=
for /f "delims=" %%s in (data.txt) do (
set line=%%s
set currentblock=!line:~1,13!
if "!line:~0,1!" EQU "I" (
if "!previousblock!" NEQ "!currentblock!" (
set /A outputcount=!outputcount!+1
)
)
echo !line!>>output!outputcount!.txt
set previousblock=!currentblock!
)
e.g。
D:\scripts>splitfile.bat
D:\scripts>type output*
output1.txt
IA1234567890A XX33 AZE
bla1 XX34 DES
bla2 XX34 DES
bla3 XX34 DES
FA1234567890A XX35 AZE
IA1234567890A XX36 AZE
bla4 XX34 DES
bla5 XX34 DES
bla6 XX34 DES
FA1234567890A XX37 AZE
output2.txt
IB0987654321A XX38 AZE
bla7 XX34 DES
bla8 XX34 DES
bla9 XX34 DES
FB0987654321A XX39 AZE
更新代码以使其正常工作。
答案 1 :(得分：0)
试试这个：
#!/bin/sh
## clean any split files (got created in previous runs)
rm split.*;
## define variables, ct=counter for reading next line, cnt=counter for creating split.X file and file=split filename
ct=2
cnt=1
file="split.$cnt";
## Read line with spaces, IFS=''
IFS=''
while read lineP
do
## Read next line and increment ct variable
lineN="$(sed -n "${ct}p" inputfile.txt)" && ((ct++))
## Read first character of two lines and the next 12 characters
lineP121=${lineP:0:1} && lineN121=${lineN:0:1}
lineP1212=${lineP:1:12} && lineN1212=${lineN:1:12}
## Match / Condition
if [[ "$lineP1212" != "$lineN1212" && ( "$lineP121" == "F" && "$lineN121" == "I" ) ]];
then
echo "${lineP}:" >> $file;
((++cnt));
file="split.$cnt";
else
echo -e "$lineP\n" >> $file;
fi
done < inputfile.txt
echo -e "\n\nFile created are (with contents in split.X files):\n\n"
ls -l split.* && echo && grep -n . split.* && echo
输出是：创建的文件数2 split.1和split.2文件（根据输入文件）。
File created are (with contents in split.X files. Output generated by grep -n command. You can use simple cat command if you want):
-rw-r--r-- 1 koba loki 450 Jun 3 19:01 split.1
-rw-r--r-- 1 koba loki 225 Jun 3 19:01 split.2
split.1:1:IA1234567890A XX33 AZE
split.1:3:bla1 XX34 DES
split.1:5:bla2 XX34 DES
split.1:7:bla3 XX34 DES
split.1:9:FA1234567890A XX35 AZE
split.1:11:IA1234567890A XX36 AZE
split.1:13:bla4 XX34 DES
split.1:15:bla5 XX34 DES
split.1:17:bla6 XX34 DES
split.1:19:FA1234567890A XX37 AZE:
split.2:1:IB0987654321A XX38 AZE
split.2:3:bla7 XX34 DES
split.2:5:bla8 XX34 DES
split.2:7:bla9 XX34 DES
split.2:9:FB0987654321A XX39 AZE
答案 2 :(得分：0)
如果输入文件很大，此方法应该运行得更快，因为它不会检查所有行。它还可以正确处理具有特殊批处理字符的行。
@echo off
setlocal EnableDelayedExpansion
rem Read the first line, and create a dummy previous "endLine" with same name
set /P "endName=" < test.txt
set "endName=F%endName:~1%"
set startLine=1
set "startName="
rem Redirect the input file to a code block, in order to read it
< test.txt (
rem Locate all lines that start with "I" or "F"
for /F "tokens=1,2 delims=: " %%a in ('findstr /N /B "I F" test.txt') do (
if not defined startName (
set "startName=%%b"
if "!startName:~1,12!" neq "!endName:~1,12!" (
rem New section starts: copy it to its own file
set /A lines=endLine-startLine+1
(for /L %%i in (1,1,!lines!) do (
set /P "line="
echo !line!
)) > "Part !endName:~1,12!.txt"
set "endName=F%startName:~1%"
set "startLine=%%a"
)
) else (
set "endLine=%%a"
set "endName=%%b"
set "startName="
)
)
rem Copy last section to its own file
findstr "^" > "Part !endName:~1,12!.txt"
)
输出：
C:\> type Part*.txt
Part A1234567890A.txt
IA1234567890A XX33 AZE
bla1 XX34 DES
bla2 XX34 DES
bla3 XX34 DES
FA1234567890A XX35 AZE
IA1234567890A XX36 AZE
bla4 XX34 DES
bla5 XX34 DES
bla6 XX34 DES
FA1234567890A XX37 AZE
Part B0987654321A.txt
IB0987654321A XX38 AZE
bla7 XX34 DES
bla8 XX34 DES
bla9 XX34 DES
FB0987654321A XX39 AZE