我正在尝试找到一种方法从我的服务向我的MainActivity发送一个整数值,但我无法通过互联网上的教程弄明白。我正在使用Handler来接收我从我服务中的线程发送的消息。
我在服务中使用Thread的代码:
private class ServiceThread extends Thread {
@Override
public void run() {
super.run();
try{
Log.i("Service", "TASK PERFORMED");
int x = 0;
for (int i = 0; i < 20; i++){
x += (random.nextInt(20) + 20);
}
theInteger = x/20;
Message msg = Message.obtain();
msg.what = MY_RND_INT;
msg.arg1 = theInteger;
handler.sendMessage(msg);
}catch(Exception e){
e.getMessage();
}
}
}
我尝试接收邮件的代码:
public Messenger mMessenger = new Messenger(new IncomingHandler());
class IncomingHandler extends Handler {
@Override
public void handleMessage(Message msg) {
switch (msg.what) {
case SimpleService.MY_RND_INT:
rndInt.setText(msg.arg1);
break;
default:
super.handleMessage(msg);
}
}
}
答案 0 :(得分:18)
假设您的活动和服务位于同一个包中......
// Supposing that your value is an integer declared somewhere as: int myInteger;
private void sendMessage() {
// The string "my-integer" will be used to filer the intent
Intent intent = new Intent("my-integer");
// Adding some data
intent.putExtra("message", myInteger);
LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}
@Override
public void onResume() {
super.onResume();
// This registers mMessageReceiver to receive messages.
LocalBroadcastManager.getInstance(this)
.registerReceiver(mMessageReceiver,
new IntentFilter("my-integer"));
}
// Handling the received Intents for the "my-integer" event
private BroadcastReceiver mMessageReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
// Extract data included in the Intent
int yourInteger = intent.getIntExtra("message",-1/*default value*/);
}
};
@Override
protected void onPause() {
// Unregister since the activity is not visible
LocalBroadcastManager.getInstance(this)
.unregisterReceiver(mMessageReceiver);
super.onPause();
}