Question

我已阅读了几篇帖子，但仍然无法弄清楚这里有什么问题。我有一个c ++包装器来调用sqlite。我想在创建表之前测试表是否存在，通过阅读check-in-sqlite-whether-a-table-exists，我使用以下sql语句来检查表是否存在

＆＃34; SELECT name FROM test.db WHERE type =＆＃39; table＆＃39; AND name =＆＃39; table1＆＃39;;＆＃34;

主要代码如下：

static int callback(void *db, int argc, char **argv, char **azColName){
  for(int i=0; i<argc; ++i){
    printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  return 0;
}

class SqliteAccessor {
public:
open(){ sqlite3_open("test.db", &m_db); }
createTable1(){
  string sql = "CREATE TABLE table1(one TEXT);";
  char *zErrMsg = 0;
  int rc = sqlite3_exec(m_db, sql.c_str(), callback, 0, &zErrMsg);
  if( rc != SQLITE_OK ){
    printf("SQL error: %s", zErrMsg);
    sqlite3_free(zErrMsg);
  }
}     
hasTable1(){
  string sql = "SELECT name FROM test.db WHERE type='table' AND name='table1'";
  char *zErrMsg = 0;
  int rc = sqlite3_exec(m_db, sql.c_str(), callback, 0, &zErrMsg);
  if( rc != SQLITE_OK ){
    printf("SQL error: %s", zErrMsg); // Error: no such table: test.db 
    sqlite3_free(zErrMsg);
  } 
}
private:
sqlite3* m_db;
}

main(){
  SqliteAccessor sql;
  sql.open(); // success;
  sql.createTable1(); // success;
  sql.hasTable1(); // fail
}

我也尝试过使用cli api：

sqlite3 test.db
sqlite> create table table1(one varchar(10));
sqlite> SELECT * FROM test.db;
Error: no such table: test.db
sqlite> SELECT name FROM test.db WHERE type='table' AND name='table1';
Error: no such table: test.db
// however, if I run .tables, then it is there.
sqlite> .tables
table1

它是同样的错误，但为什么会出现这样的错误？它是最新的sqlite合并版本。

Answer 1

请查看sqlite_master。

SELECT * FROM sqlite_master WHERE name LIKE '%your_table_name%'

sqlite3错误：没有这样的表：检查表是否存在时

1 个答案: