Question

大家好我试图在我的应用上创建一个能改变语言的功能（在Android上），事实是它不能很好地工作，因此我必须重启我的应用程序才能使用该语言改变应用

我想要实现的是首先选择弹出的语言，然后通知用户应用程序将重新启动以便应用更改。

这是我用来更改语言的代码段，以及应用程序在重新启动时保存更改语言的代码：

public class LocalizationUpdaterActivity extends Activity {

private String[] languages = { "English", "Francais", "Espanol", "Ivrit" };
/**
 * Called when the activity is first created.
 */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_langues);

    SharedPreferences sp = this.getApplicationContext().getSharedPreferences("loginSaved", Context.MODE_PRIVATE);
    final SharedPreferences.Editor editor = sp.edit();


    Spinner spinner = (Spinner) findViewById(R.id.spinner1);
    spinner.setPrompt("select language");

    ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
            android.R.layout.simple_spinner_item, languages);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);

    spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {

        public void onItemSelected(AdapterView arg0, View arg1,
                                   int arg2, long arg3) {
            Configuration config = new Configuration();
            switch (arg2) {
                case 0:
                    config.locale = Locale.ENGLISH;
                    editor.putString("Langues", "en_US");
                    break;
                case 1:
                    config.locale = Locale.FRENCH;
                    editor.putString("Langues", "fr_FR");
                    break;
                case 2:
                    config.locale = new Locale("es_ES");
                    editor.putString("Langues", "es_ES");
                    break;
                case 3:
                    config.locale = new Locale("he", "IL");
                    editor.putString("Langues", "he_IL");
                    break;
                default:
                    config.locale = Locale.ENGLISH;
                    editor.putString("Langues", "en_US");
                    break;
            }
            getResources().updateConfiguration(config, null);
        }

        public void onNothingSelected(AdapterView arg0) {
            // TODO Auto-generated method stub

        }
    });
}

}

Answer 1

当您在共享偏好中存储语言时，您只需在对话框中调用此代码段＆＃34;确定＆＃34;点击事件：

Intent i = new Intent(MyClass.this, MyClass.class);
startActivity(i);

Answer 2

我遇到了与你目前面临的问题相同的问题为了实现这一点，我在我的BaseActivity中实现了一个BroadcastReceiver（所有活动都从中扩展），当接收到特定命令时，它将完成活动。
这将在发送命令时完成所有活动，从而终止应用程序。

要立即重新启动它，您只需为想要的活动创建一个意图，并在您杀死该应用程序的同一个函数中启动该活动。

一个简单的例子如下所示：

public abstract class BaseActivity extends FragmentActivity {

    private KillReceiver killReceiver;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        killReceiver = new KillReceiver();
        registerReceiver(killReceiver, IntentFilter.create("kill", "content://all"));
    }

    @Override
    protected void onDestroy() {
        super.onDestroy();
        unregisterReceiver(killReceiver);
    }

    private final class KillReceiver extends BroadcastReceiver {
        @Override
        public void onReceive(Context context, Intent intent) {
            finish();
        }
    }
}

这两个函数可用于终止/重启应用程序。

public void killApplication(Activity activity) {
    //Broadcast the command to kill all activities
    Intent intent = new Intent("kill");
    intent.setType("content://all");
    activity.sendBroadcast(intent);
}

public void restartApplication(Activity activity) {
    killApplication(activity);

    //Start the launch activity
    Intent i = activity.getBaseContext().getPackageManager().getLaunchIntentForPackage(activity.getBaseContext().getPackageName());
    activity.startActivity(i);
}

这种做法从来没有让我失望，我也没有发现任何问题。

弹出窗口将重启App Android

2 个答案: