Question

我的报告中有一个名为@Animal的多值参数，其中包含（＆＃39; Cat＆＃39;，＆＃39; Dog＆＃39;，＆＃39; Mouse＆＃39;）。

内部数据集我需要获得“Cat＆＃39;，Dog＆＃39;”，＃39;鼠标＆＃39;并将其存储到@AnimalName表变量中。

＆＃34;硬编码＆＃34;方式是：

DECLARE @AnimalName TABLE (Name nvarchar (10))
INSERT INTO @AnimalName SELECT ('Cat');
INSERT INTO @AnimalName SELECT ('Dog');
INSERT INTO @AnimalName SELECT ('Mouse');

我知道我可以直接在我的数据集中使用@Animal，我之所以这样做是因为我试图提高报告的性能。许多多值参数将使报告永远运行。

有没有人知道如何（语法）获取@Animal数据值并将其存储到数据集内的表变量@AnimalName中？

谢谢堆！

Answer 1

将逗号分隔的字符串传递给存储过程，并在存储过程中使用表值函数将多值参数转换为表格。

CREATE PROC GetAllAnimals 
                      @AnimalList nvarchar(max)
AS

DECLARE @Animals TABLE (Animal nvarchar(10))
INSERT INTO @Animals SELECT * FROM dbo.fnGetValueListFromMultiSelect(@AnimalList)

然后使用@Animals表在查询中进行内连接

下面声明的函数。

对于整数（或ID）值

CREATE FUNCTION [dbo].[fnGetIdListFromMultiSelect](@String nvarchar(MAX))
RETURNS @Results TABLE ([Id] int)
AS
    BEGIN
    DECLARE @Delimiter CHAR(1) 
    DECLARE @INDEX INT
    DECLARE @SLICE nvarchar(4000)

    IF @String IS NULL RETURN   
    SET @Delimiter = ','
    SET @INDEX = 1  

    WHILE @INDEX !=0
        BEGIN 
         -- GET THE INDEX OF THE FIRST OCCURENCE OF THE SPLIT CHARACTER
         SELECT @INDEX = CHARINDEX(@Delimiter,@STRING)
         -- NOW PUSH EVERYTHING TO THE LEFT OF IT INTO THE SLICE VARIABLE
         IF @INDEX !=0
         BEGIN
          SELECT @SLICE = LEFT(@STRING,@INDEX - 1)
          -- CHOP THE ITEM REMOVED OFF THE MAIN STRING
          SELECT @STRING = RIGHT(@STRING,LEN(@STRING) - @INDEX)
         END
         ELSE
          SELECT @SLICE = @STRING                   
            -- PUT THE ITEM INTO THE RESULTS SET
            INSERT INTO @Results([Id]) VALUES(CAST(@SLICE AS INT))          
         -- BREAK OUT IF WE ARE DONE
         IF LEN(@STRING) = 0 BREAK
    END
    RETURN
END

对于字符串值

CREATE FUNCTION [dbo].[fnGetValueListFromMultiSelect](@String nvarchar(MAX))
RETURNS @Results TABLE ([Item] nvarchar(128) Primary Key)
AS
    BEGIN
    DECLARE @Delimiter CHAR(1) 
    DECLARE @INDEX INT
    DECLARE @SLICE nvarchar(4000)

    SET @Delimiter = ','
    SET @INDEX = 1

    WHILE @INDEX !=0
        BEGIN 
         -- GET THE INDEX OF THE FIRST OCCURENCE OF THE SPLIT CHARACTER
         SELECT @INDEX = CHARINDEX(@Delimiter,@STRING)
         -- NOW PUSH EVERYTHING TO THE LEFT OF IT INTO THE SLICE VARIABLE
         IF @INDEX !=0
         BEGIN
          SELECT @SLICE = LEFT(@STRING,@INDEX - 1)
          -- CHOP THE ITEM REMOVED OFF THE MAIN STRING
          SELECT @STRING = RIGHT(@STRING,LEN(@STRING) - @INDEX)
         END
         ELSE
          SELECT @SLICE = @STRING
         -- PUT THE ITEM INTO THE RESULTS SET
         INSERT INTO @Results([Item]) VALUES(@SLICE)

         -- BREAK OUT IF WE ARE DONE
         IF LEN(@STRING) = 0 BREAK
    END
    RETURN
END

SSRS报告：获取参数数据值并将其存储到数据集中的变量中

1 个答案: