是否可以使用SLRequest分享视频？
我可以使用相同的
分享图像SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:requestURL parameters:message];
if (isImage)
{
NSData *data = UIImagePNGRepresentation(imgSelected);
[postRequest addMultipartData:data withName:@"media" type:@"image/png" filename:@"TestImage.png"];
}
postRequest.account = account;
[postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error)
{
if (!error)
{
NSLog(@"Upload Sucess !");
}
}];
答案 0 :(得分：4)
我一直在阅读Twitter视频上传API文档，它非常简单。您基本上需要向其API发出3个POST请求。您上传的视频也限制为15 MB。
使用此端点上传需要至少3次呼叫，一次到 初始化请求，返回media_id，一个或多个调用 附加/上传二进制或base64编码数据，以及最后一次调用 完成上传并使media_id与其他资源一起使用。
所以它的工作原理如下：
请求1：发送包含视频大小的初始化请求（以字节为单位）。这将返回我们必须在请求2和3中使用的媒体ID号。
请求2：使用请求1中返回的媒体ID号上传视频数据。
请求3：视频上传完成后，将“FINALIZE”请求发回Twitter API。这让Twitter API知道视频文件的所有块都已完成上传。
注意 Twitter API接受“chunk”中的视频上传。因此，如果您的视频文件很大，您可能需要将其拆分为多个文件，因此您必须多次重复“请求2”（不要忘记每次都增加“segment_index”数字）。< / p>
我已经开始编写以下代码了。尝试一下并尝试一下。我稍后会更新我的答案以改进它。
-(void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
// Assign the mediatype to a string
NSString *mediaType = [info objectForKey:UIImagePickerControllerMediaType];
// Check the media type string so we can determine if its a video
if ([mediaType isEqualToString:@"public.movie"]) {
NSURL *videoURL = [info objectForKey:UIImagePickerControllerMediaURL];
NSData *webData = [NSData dataWithContentsOfURL:videoURL];
// Get the size of the file in bytes.
NSString *yourPath = [NSString stringWithFormat:@"%", videoURL];
NSFileManager *man = [NSFileManager defaultManager];
NSDictionary *attrs = [man attributesOfItemAtPath:yourPath error: NULL];
UInt32 result = [attrs fileSize];
//[self tweetVideoStage1:webData :result];
[self tweetVideo:webData :result :1 :@"n/a"];
}
}
-(void)tweetVideo:(NSData *)videoData :(int)videoSize :(int)mode :(NSString *)mediaID {
NSURL *twitterVideo = [NSURL URLWithString:@"https://upload.twitter.com/1.1/media/upload.json"];
// Set the parameters for the first twitter video request.
NSDictionary *postDict;
if (mode == 1) {
postDict = @{@"command": @"INIT",
@"total_bytes" : videoSize,
@"media_type" : @"video/mp4"};
}
else if (mode == 2) {
postDict = @{@"command": @"APPEND",
@"media_id" : mediaID,
@"segment_index" : @"0",
@"media" : videoData };
}
else if (mode == 3) {
postDict = @{@"command": @"FINALIZE",
@"media_id" : mediaID };
}
SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:requestURL:twitterVideo parameters:postDict];
// Set the account and begin the request.
postRequest.account = account;
[postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
if (!error) {
if (mode == 1) {
// Parse the returned data for the JSON string
// which contains the media upload ID.
NSMutableDictionary *returnedData = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableContainers error:&error]
NSString *tweetID = [NSString stringWithFormat:@"%@", [returnedData valueForKey:@"media_id_string"]];
[self tweetVideo:videoData :result :2 :tweetID];
}
else if (mode == 2) {
[self tweetVideo:videoData :result :3 :mediaID];
}
}
else {
NSLog(@"Error stage %d - %", mode, error);
}
}];
}
更新 - Twitter API错误 - https://dev.twitter.com/overview/api/response-codes
在回答您的第一条评论时，错误503表示Twitter服务器已超载且无法立即处理您的请求。
503服务不可用Twitter服务器已启动但已超载 有请求。稍后再试。
答案 1 :(得分：4)
我知道如何使用新API将视频上传到Twitter。我尝试过它，它有效。
请检查：https://github.com/liu044100/SocialVideoHelper
你只需要调用这个类方法。
+(void)uploadTwitterVideo:(NSData*)videoData account:(ACAccount*)account withCompletion:(dispatch_block_t)completion;
希望它可以解决您的问题。
最诚挚的问候。
答案 2 :(得分：2)
一直在寻找在Twitter解决方案上分享以下功能的视频：
由于我无法找到一个符合要求的会议，所以我决定写一个。
https://github.com/mtrung/TwitterVideoUpload
我现在已经测试了一段时间，对我来说效果很好。
希望它有所帮助，
问候。
答案 3 :(得分：1)
在@Dan回答中尝试这个。它没有经过测试，但我认为它可以工作。
使用Cocoa-pods ： pod'TwitterKit'
如果您不使用Pod，请尝试使用fabric
//for Extern call
//Mode is 1
//MediaId is 0
- (void)uploadTwitterVideo:(NSData*)videoData videoTitle:(NSString *)title desc:(NSString *)desc withMode:(int)mode mediaID:(NSString *)mediaID withCompletion:(dispatch_block_t)completion
{
NSString *twitterPostURL = @"https://upload.twitter.com/1.1/media/upload.json";
NSDictionary *postParams;
if (mode == 1) {
postParams = @{@"command": @"INIT",
@"total_bytes" : [NSNumber numberWithInteger: videoData.length].stringValue,
@"media_type" : @"video/mp4"};
} else if (mode == 2) {
postParams = @{@"command": @"APPEND",
@"media_id" : mediaID,
@"segment_index" : @"0"};
} else if (mode == 3) {
postParams = @{@"command": @"FINALIZE",
@"media_id" : mediaID };
} else if (mode == 4) {
postParams = @{@"status": desc,
@"media_ids" : @[mediaID]};
}
TWTRAPIClient *twitterInstance = [[Twitter sharedInstance] APIClient];
NSError *error;
NSURLRequest *requestTw = [twitterInstance URLRequestWithMethod:@"POST" URL:twitterPostURL parameters:postParams error:&error];
[twitterInstance sendTwitterRequest:requestTw completion:^(NSURLResponse * _Nullable response, NSData * _Nullable data, NSError * _Nullable connectionError) {
NSLog(@"HTTP Response: %li, responseData: %@", (long)response, [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding]);
if (error) {
NSLog(@"There was an error:%@", [error localizedDescription]);
} else {
if (mode == 1) {
NSMutableDictionary *returnedData = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&connectionError];
NSString *mediaIDResponse = [NSString stringWithFormat:@"%@", [returnedData valueForKey:@"media_id_string"]];
NSLog(@"stage one success, mediaID -> %@", mediaID);
[self uploadTwitterVideo:videoData videoTitle:title desc:desc withMode:2 mediaID:mediaIDResponse withCompletion:completion];
} else if (mode == 2) {
[self uploadTwitterVideo:videoData videoTitle:title desc:desc withMode:3 mediaID:mediaID withCompletion:completion];
} else if (mode == 3) {
[self uploadTwitterVideo:videoData videoTitle:title desc:desc withMode:4 mediaID:mediaID withCompletion:completion];
} else if (mode == 4) {
DispatchMainThread(^(){completion();});
}
}
}];
}
此API的工作原理如下。
- 安装应用程序（twitter）时以及未安装时登录
- 首先从设置
获取凭据选中此case
答案 4 :(得分：0)
<强>夫特
非常简单。
首先，您需要登录您的Twitter帐户。转到电话设置，然后单击Twitter应用程序并登录。
现在只需将videoUpload func调用到任何地方
视频或分块上传方法 Reference
替换该代码上的视频类型/扩展名 并仔细阅读所有twitter requirements。
var twitterAccount = ACAccount()
func videoUpload{
let path = Bundle.main.path(forResource: "file-Name", ofType:"mp4")
let filePath = path
var fileSize = UInt64()
do {
//return [FileAttributeKey : Any]
let attr = try FileManager.default.attributesOfItem(atPath: filePath!)
fileSize = attr[FileAttributeKey.size] as! UInt64
//if you convert to NSDictionary, you can get file size old way as well.
let dict = attr as NSDictionary
fileSize = dict.fileSize()
} catch {
print("Error: \(error)")
}
let accountStore = ACAccountStore()
let twitterAccountType = accountStore.accountType(withAccountTypeIdentifier: ACAccountTypeIdentifierTwitter)
accountStore.requestAccessToAccounts(with: twitterAccountType, options: nil) { (granted, error) in
if granted {
let accounts = accountStore.accounts(with: twitterAccountType)
if (accounts?.count)! > 0 {
self.twitterAccount = accounts?.last as! ACAccount
}}}
twitterAccount = Twitter.sharedInstance().sessionStore.session() as! ACAccount
uploadVideoToTwitter(videoURL: URL(string : path!)! as NSURL, fileSize: UInt32(fileSize))
}
func uploadVideoToTwitter(videoURL:NSURL,fileSize: UInt32) {
if let videoData = NSData(contentsOfFile: videoURL.path!){
self.tweetVideoInit(videoData: videoData, videoSize: Int(fileSize))
}
}
func tweetVideoInit(videoData:NSData,videoSize:Int) {
let uploadURL = NSURL(string:"https://upload.twitter.com/1.1/media/upload.json")
var params = [String:String]()
params["command"] = "INIT"
params["total_bytes"] = String(videoData.length)
params["media_type"] = "video/mp4"
let postRequest = SLRequest(forServiceType: SLServiceTypeTwitter,
requestMethod: SLRequestMethod.POST,
url: uploadURL as URL!,
parameters: params)
postRequest?.account = self.twitterAccount;
postRequest?.perform(handler: { ( responseData, urlREsponse,error) in
if let err = error {
print(error as Any)
}else{
do {
let object = try JSONSerialization.jsonObject(with: responseData! as Data, options: .allowFragments)
if let dictionary = object as? [String: AnyObject] {
if let tweetID = dictionary["media_id_string"] as? String{
self.tweetVideoApped(videoData: videoData, videoSize: videoSize, mediaId: tweetID, chunk: 0)
}
}
}
catch {
print(error)
}
}
})
}
func tweetVideoApped(videoData:NSData,videoSize:Int ,mediaId:String,chunk:NSInteger) {
let uploadURL = NSURL(string:"https://upload.twitter.com/1.1/media/upload.json")
var params = [String:String]()
params["command"] = "APPEND"
params["media_id"] = mediaId
params["segment_index"] = String(chunk)
let postRequest = SLRequest(forServiceType: SLServiceTypeTwitter,
requestMethod: SLRequestMethod.POST,
url: uploadURL as URL!,
parameters: params)
postRequest?.account = self.twitterAccount
postRequest?.addMultipartData(videoData as Data!, withName: "media", type: "video/mov", filename:"mediaFile")
postRequest?.perform(handler: { ( responseData, urlREsponse,error) in
if let err = error {
print(err)
}else{
self.tweetVideoFinalize(mediaId: mediaId)
}
})
}
func tweetVideoFinalize(mediaId:String) {
let uploadURL = NSURL(string:"https://upload.twitter.com/1.1/media/upload.json")
var params = [String:String]()
params["command"] = "FINALIZE"
params["media_id"] = mediaId
let postRequest = SLRequest(forServiceType: SLServiceTypeTwitter,
requestMethod: SLRequestMethod.POST,
url: uploadURL as URL!,
parameters: params)
postRequest?.account = self.twitterAccount;
postRequest?.perform(handler: { ( responseData, urlREsponse,error) in
if let err = error {
print(err)
}else{
do {
let object = try JSONSerialization.jsonObject(with: responseData! as Data, options: .allowFragments)
if let dictionary = object as? [String: AnyObject] {
self.postStatus(mediaId: mediaId)
}
}
catch {
print(error)
}
}
})
}
func postStatus(mediaId:String) {
let uploadURL = NSURL(string:"https://api.twitter.com/1.1/statuses/update.json")
var params = [String:String]()
params["status"] = "my first Video Upload"
params["media_ids"] = mediaId
let postRequest = SLRequest(forServiceType: SLServiceTypeTwitter,
requestMethod: SLRequestMethod.POST,
url: uploadURL as URL!,
parameters: params)
postRequest?.account = self.twitterAccount;
postRequest?.perform(handler: { ( responseData, urlREsponse,error) in
if let err = error {
print(err)
}else{
do {
let object = try JSONSerialization.jsonObject(with: responseData! as Data, options: .allowFragments)
if let dictionary = object as? [String: AnyObject] {
print("video uploaded")
}
}
catch {
print(error)
}
}
})
}
答案 5 :(得分：-1)
我能够成功将视频上传到Twitter！ 以下是Twitter文档中提到的步骤：
申请推特账号
accountStore.requestAccessToAccounts(with: twitterAccountType,options:nil){(granted, error) in
POST媒体/上传（INIT）
params["command"] = "INIT"
params["total_bytes"] = String(videoData.length)
params["media_type"] = "video/mov"
POST媒体/上传（APPEND）
params["command"] = "APPEND"
params["media_id"] = mediaId
params["segment_index"] = String(chunk)
POST媒体/上传（FINALIZE）
params["command"] = "FINALIZE"
params["media_id"] = mediaId
POST媒体/上传
params["status"] = twitterDescription
params["media_ids"] = mediaId
这是Twitter文档链接https://dev.twitter.com/rest/media/uploading-media.html
请使用SLRequest在此处详细解决上传到Twitter的视频。
http://swiftoverflow.blogspot.in/2017/04/upload-video-to-twitter-using-slrequest.html