Question

在这里阅读了很多帖子之后，关于如何在我的html表单中捕获Select值，我理解了原理，但我似乎无法在下面的代码中完美地执行它。
$ selected_val未被追加。也许它是空的？我错过了什么？提前谢谢。

期望的结果：
test@test.com是 A-user ，

当前结果：
test@test.com是一个，

以下是我的HTML表单的外观：

<form method="POST" class="subscription-form form-inline  id="subscribe" role="form">

<h4 class="subscription-success"><i class="icon_check"></i> Thank you for requesting... </h4>
<h4 class="subscription-error">Something Wrong!</h4>

<select name="usertype" class="form-control input-box">
    <option selected value="A-user">I'm an A user</option>
    <option value="B-user">I'm an B user</option>
    <option value="C-user">I'm an C user</option>
</select>
<input type="email" name="email" id="subscriber-email" placeholder="Your Email" class="form-control input-box">

<button type="submit" name="submit" id="subscribe-button" class="btn btn-default standard-button">Submit</button>

</form>

这是我的php：

<?php 
   if ( isset($_POST['email']) && filter_var($_POST['email'], FILTER_VALIDATE_EMAIL) ) {

    $selected_val = $_POST['usertype'];  // Storing Selected Value In Variable

    $e_mail = $_POST['email'] . " is a " . $selected_val . " ," . "\n";
file_put_contents('email-list.txt', $e_mail, FILE_APPEND | LOCK_EX);
} 
?>

Answer 1

您的表单缺少方法属性

发布方法应该在那里

<form action="your.php" method="post">

Answer 2

$(document).ready(function() { $.getScript("vehicle_data.json", function() { // Pay attention. In this case, you work with carInfo // variable because it has been executed as a script, // but not loaded as a JSON file. $.each(carInfo, function() { $("ul").append("<li>Car ID: " + this[carInfo[0].carId]); }); }); });元素应具有<form>属性，如

method

在您的PHP代码中

注意，用户将点击提交按钮，然后检查

<form method="POST" class="subscription-form form-inline wow fadeInRight animated" data-wow-offset="10" data-wow-duration="1.5s" id="subscribe" role="form">

无法捕获表单选择值，php

2 个答案: