图库无法正常工作

时间:2015-06-02 23:12:55

标签: javascript php mysql

我有一个图片库,我用javascript函数调用它,它工作正常。现在我将在PHP中创建它,以便用户可以更改和删除一些图像。我决定仍然在javascript中执行它,只是在PHP中传递参数。该函数将图像名称作为参数,并在页面上的window.onload中将其传递给php。

问题:

每个画廊都有4张照片。我应该有3个画廊,每个画廊有4张不同的图片,相反,我有4个画廊,每个画廊都有重复的图像。 php使用相同的参数执行JS函数4次,因为我的表中有4个值。

我怎么能做对的?

以下是代码:

function galerias(query){
    var galeria = new Array();

        var imgs = document.querySelector("#gallery");
        var x = 1;

            imgs.innerHTML += "<div class='row'>";
            imgs.innerHTML += "<div class='eight columns'>";
            imgs.innerHTML += "<h4>Galeria "+x+"</h4>"

        for(var i = 0; i <= 3; i++){
            galeria[i] = query;
        }


        for(var i = 0; i < galeria.length; i++){
            imgs.innerHTML += "<img src='img/"+query+"'class='imgs-galeria'>";
        }

        imgs.innerHTML += "</div>";
        imgs.innerHTML += "</div>";
        imgs.innerHTML += "<a class='row' href='pics.html?gal="+x+"'><div class='twelve columns link'><p>Veja mais</p></div>";
        x++;

}

//this is in my window.onload, so it loads the galleries with the page:

    <?php
        foreach($galeria_1 as $result){
            echo'galerias("'.$result['nome'].'");';
        }
    ?>

//this is in my separate file that make the DB functions:
    function consultarDados($query){
        $dbResult = array();
        $conexao = mysql_connect($this->host, $this->usuario, $this->senha);
        mysql_select_db($this->banco, $conexao);
        $rs = mysql_query($query, $conexao);
            while($rows = mysql_fetch_assoc($rs)){
                array_push($dbResult, $rows);
            }
        return $dbResult;
        mysql_close($conexao);
    }

//and this is how i call it in my galleries page:
<?php 
    include 'connectDB.php';
    $conexao = new connectDb();
    $galeria_1= $conexao->consultarDados('select * from portfolio where gal= 1 and theme= 1');
?>

0 个答案:

没有答案