我的图片如下:
给定的imrgb = 320 * 512 * 3 double; color_map = 64 * 3 double;使用后
[X, map] = rgb2ind(imrgb, color_map);
我得到X = 320 * 512 uint8。图像太大,无法进一步处理。我的 问题是如何将图像平移和缩放到32 * 32像素的标准尺寸而不会丢失重要信息(我的意思是图像的非黑色部分都是重要信息)?
答案 0 :(得分:2)
这是一个解决方案,我将每个大脑平铺为32x32
图像。评论解释了代码。但基本的想法是......
使用block proc
将大图像分割成5x8网格,因为它有5行大脑和8列大脑。我将这些图片中的每一个称为瓷砖
将每个磁贴调整为32x32
使用mat2cell
这是代码
im = rgb2gray(imrgb);
max_rows = 32;
max_cols = 32;
%I assume every picture has 40 brains, 5 rows and 8 columns
rows_brains = 5;
cols_brains = 8;
[m n] = size(im);
%define the resize function to take the 'block_struct' image and resize
%it to max_rows x max_cols
fun = @(block_struct) imresize(block_struct.data,[max_rows max_cols]);
%blockproc will split the image into tiles. Each tile should hold one brain
%image. Then we resize that tile to a 32x32 tile using the resize function
%we defined earlier
I2 = blockproc(im,[m/rows_brains n/cols_brains],fun);
%split the image with small tiles into individual pictures
%each cell of indiv_brains will contain a 32x32 image of only one brain
indiv_brains = mat2cell(I2,max_rows*ones(1,rows_brains),max_cols*ones(1,cols_brains));
%displays all the brains
figure(1);
for ii=1:1:rows_brains
for jj=1:1:cols_brains
subplot(rows_brains, cols_brains, (ii-1)*cols_brains + jj);
imshow(indiv_brains{ii,jj});
end
end
结果,这些单独的图像中的每一个都是32x32