Question

服务器端：我通过ajax接收用户列表，我试图通过套接字发出它，但只发送到同一个客户端。像这样的东西

io.sockets.emit("users list", {users: users, me : req.me});//This work, but to all users

socket.emit("users list", {users: users, me : req.me}); //Im trying something like this

代码

//Receive user list
    app.post('/', function(request, response){
        response.setHeader('Access-Control-Allow-Origin', 'http://localhost'); //To allow response
        var req = JSON.parse(request.body.data);
        if(typeof req != "object") {
            response.send({status: false, msg: "Error on load user list"});
        } else {
            socket.id = req.me.id;
            req.users.data.forEach(function(user) {
                if(users[user.id] == null)
                    users[user.id] = user;
            });

            //io.sockets.emit("users list", {users: users, me : req.me});//This work, but to all users
            socket.emit("users list", {users: users, me : req.me}); //Im trying something like this
        }
        response.send({status: true, msg: ""});// echo the result back
    });

我也想知道是否有一些最好的方法来做到这一点......

Answer 1

您可以尝试将数据发送到特定套接字，如下所示：

io.sockets.socket（socket.id）.emit（＆＃34; users list＆＃34;，{users：users，me：req.me}）;

Socket使用Node.js发出ajax接收的数据

1 个答案: