Question

我写了一个shell函数，如下所示

extract () {        
    awk -vbegin="${1}" '/begin/ {flag=1;next} /=====/{flag=0} flag {
        print
    }   
    ' "$2" | egrep "$3" | egrep -v "$4"
}

然而，当我打电话

extract "Begin Criteria" "First" "Second" "Third1|Third2"

第一个变量“Begin Criteria”似乎无法在/ begin /

中解析

我怎样才能使我的通话类似？

awk '/Begin Criteria/ {flag=1;next} /=====/{flag=0} flag {
        print
}
' First | egrep 'Second' | egrep -v 'Third1|Third2'

Raw_data_file

First Bundle ====
    First 1       
        Second 1
            Third_1 1
            Third_2 1
=====

Second Bundle ====
    Second 1   
        Third_1 1
        Third_2 1
        Third_3 1
=====

Third Bundle ====
    Third_1 1  
    Third_2 1 
    Third_3 1
=====

First Bundle ====
    First 2           
        Second 2
            Third_1 2
            Third_2 2
=====

Second Bundle ====
    Second 2   
        Third_1 2
        Third_2 2
        Third_3 2
=====

Third Bundle ====
    Third_1 2   
    Third_2 2
    Third_3 2
=====

用法

extract "Second Bundle" Raw_data_file "Second" "Third1|Third2" Second.out
extract "Third Bundle" Raw_data_file "Third1|Third2" "" Third.out
extract "First Bundle" Raw_data_file "" "" First.out

预期

First.out

First 1       
    Second 1
        Third_1 1
        Third_2 1
First 2       
    Second 2
        Third_1 2
        Third_2 2

Second.out

Second 1   
Second 2

Third.out

Third_1 1   
Third_2 1   
Third_1 2   
Third_2 2

Answer 1

要在awk中使用变量，您可以执行以下操作：

form.getvalue('toggle-event')

当您使用awk -vbegin="${1}" '$0 ~ begin {flag=1;next} /=====/{flag=0} flag { print }'时，您确实将文字/begin/与变量begin完全匹配。

Answer 2

当你使用awk时，你永远不需要使用管道来/从grep等，因为awk可以做任何有用的事情，grep可以做。将您的功能重写为：

extract () {        
    awk -v begin="$1" -v plus="$3" -v minus="$4" '
        /=====/ {flag=0}
        flag && ($0 ~ plus) && ($0 !~ minus)
        $0 ~ begin {flag=1}
    ' "$2"
}

未经测试，因为您没有提供任何样本输入或预期输出。

shell函数内的awk变量

2 个答案: