我从数据库中获取所有值作为数组。作为一个庞大的数据库,我只是展示了两行供参考。
所以数组就是这样做print_r($data);
array(
[0] => Array
(
[listing_id] => 5975
[category_id] => A la Carte|Bar|Banquet|Champagne Bar|Cajun Creole|German
[listing_name] => test-chris
[image_name] => SBCTR Logo.jpg
[address] => 1 surfe parade
[phone] => 0402331482
)
[1] => Array
(
[listing_id] => 5974
[category_id] =>
[listing_name] => Charlie Lovett
[image_name] => SBCTR Logo.jpg
[address] =>
[phone] =>
)
[2] => Array
(
[listing_id] => 5973
[category_id] => Banquet|Champagne Bar
[listing_name] => Charlie Lovett
[image_name] => SBCTR_1234 Logo.jpg
[address] =>
[phone] => 1231234567
)
)
现在我要导出为csv。所以我制作了像这样的PHP代码
function export_to_csv($data, $filename="data.csv", $delim = ',', $newline = "\n", $enclosure = '' ) {
$string_to_export = '';
$c = 0;
foreach( $data as $row) {
$string_to_export .= $enclosure.implode($enclosure.$delim.$enclosure, ( $c ? array_values($row) : array_keys($row)) ).$enclosure.$newline;
$c++;
}
header('Content-type: text/csv;charset=utf-8');
header('Content-Disposition: attachment; filename='.$filename);
header("Cache-Control: no-cache");
//echo "\xEF\xBB\xBF";
echo $string_to_export;
exit();
}
export_to_csv($data, "data.csv");
现在,当我打开csv时,我看到如果连续没有列的数据,那么下一列只是转移到后退一步。喜欢这个
listing_id category_id listing_name image_name address phone
5975 A la Carte|Bar.... test-chris SBCTR Logo.jpg 1 surfe parade 1482
5974 Charlie Lovett SBCTR Logo.jpg
5973 Banquet|Champagne Bar Charlie Lovett SBCTR_1234 Logo.jpg 1231234567
正如您所看到的,数据正在转移到第2行和第3行的previus列。那么有人可以告诉我如何解决这个问题。抱歉,我无法更改数据库。任何帮助和建议都会非常明显。感谢