我正在尝试为用户发送欢迎信息。
我的计划是:
div
消息; div
消息。我写了这段代码:
我的Cookie代码
<script type="text/javascript">
function createCookie(name, value, days) {
if (days) {
var date = new Date();
date.setTime(date.getTime() + (days * 24 * 60 * 60 * 1000));
var expires = "; expires=" + date.toGMTString();
} else var expires = "";
document.cookie = name + "=" + value + expires + "; path=/";
}
function readCookie(name) {
var nameEQ = name + "=";
var ca = document.cookie.split(';');
for (var i = 0; i < ca.length; i++) {
var c = ca[i];
while (c.charAt(0) == ' ') c = c.substring(1, c.length);
if (c.indexOf(nameEQ) == 0) return c.substring(nameEQ.length, c.length);
}
return null;
}
function eraseCookie(name) {
createCookie(name, "", -1);
}
</script>
我的显示代码
<script type="text/javascript">
function showbox() {
document.getElementById("apDiv1").style.visibility = "visible";
}
setTimeout("showbox()", 30000); // after 5 secs
</script>
<script type="text/javascript">
if (!readCookie('visitedPreviously')) {
showbox();
//document.write(' Your Message Goes Here And You See It Only Once ');
createCookie('visitedPreviously', 'visitedPreviously', 3); // 365 days persistence
}
//eraseCookie('visitedPreviously'); // FOR TEST PURPOSES
</script>
我的问题是当访问者第一次访问该页面时,div立即显示(30秒) - 不起作用
但是当回访者再次访问页面时div
会在30秒后显示。
我想第一次用户访问,以便在30秒后显示div消息。
请帮帮我。
答案 0 :(得分:3)
根据您的解释,您希望仅在30秒后向新用户显示一个对话框。因此,您需要将代码更改为:
<script type="text/javascript">
function showbox() {
document.getElementById("apDiv1").style.visibility = "visible";
}
if (!readCookie('visitedPreviously')) { //if he/she is a new user
setTimeout("showbox()", 30000); // after 30 secs
//document.write(' Your Message Goes Here And You See It Only Once ');
createCookie('visitedPreviously', 'visitedPreviously', 3); // 365 days persistence
}
//eraseCookie('visitedPreviously'); // FOR TEST PURPOSES
</script>
答案 1 :(得分:2)
您需要删除showbox周围的引号。
这是setTimeout fnction的语法,
setTimeout(function,milliseconds,param1,param2,...)
setTimeout要求第一个参数是函数调用。
function showbox() {
document.getElementById("apDiv1").style.visibility = "visible";
alert();
}
setTimeout(showbox, 30000); // after 5 secs
if (!readCookie('visitedPreviously')) {
//I added a set timeout here which is what you need
setTimeout(showbox, 30000); // after 5 secs
//document.write(' Your Message Goes Here And You See It Only Once ');
createCookie('visitedPreviously', 'visitedPreviously', 3); // 365 days persistence
}
//eraseCookie('visitedPreviously'); // FOR TEST PURPOSES
&#13;
答案 2 :(得分:1)
删除"showbox()"
中的引号和括号。像这样:
setTimeout(showbox, 30000);
答案 3 :(得分:1)
我已经更正了下面的代码,您在检查过Cookie之前调用了setTimeout!
function showbox() {
document.getElementById("apDiv1").style.visibility = "visible";
}
if (!readCookie('visitedPreviously')) {
setTimeout("showbox()", 30000); // after 30 seconds
//document.write(' Your Message Goes Here And You See It Only Once ');
createCookie('visitedPreviously', 'visitedPreviously', 3); // 365 days persistence
}
&#13;
请试一试。
答案 4 :(得分:0)
您不需要showbox
周围的引号:
setTimeout(showbox, 30000);
文档:https://developer.mozilla.org/en-US/docs/Web/API/WindowTimers/setTimeout
答案 5 :(得分:0)
您应该将显示代码修改为:
<script type="text/javascript">
function showbox() {
document.getElementById("apDiv1").style.visibility = "visible";
}
setTimeout(showbox, 30000); // after 5 secs
</script>
<script type="text/javascript">
if (!readCookie('visitedPreviously')) {
//I added a set timeout here which is what you need
setTimeout(showbox, 30000); // after 5 secs
//document.write(' Your Message Goes Here And You See It Only Once ');
createCookie('visitedPreviously', 'visitedPreviously', 3); // 365 days persistence
}
//eraseCookie('visitedPreviously'); // FOR TEST PURPOSES
</script>
请注意,上面的更改是:
//我在这里添加了一个设置超时,这就是你需要的
setTimeout(showbox,30000); // 5秒后
将函数作为字符串发送是一种不错的做法,就像在设置超时中一样。
答案 6 :(得分:0)
您需要将代码修改为
int main()
{
derived_op d;
base_op<base_info<derived_info> > b;
}