你能解释一下Java中Boxing和Generics的奇怪行为吗?

时间:2015-06-02 07:33:57

标签: java generics

根据Java docs,以下代码应该导致编译错误:

import java.util.*;

public class GenericTest1 {

    // Add T-array of objects to collection<T>
    static <T> void fromArrayToCollection(T[] a, Collection<T> c) {
        for (T o : a) {
            c.add(o);
        }
    }

   public static void main( String[] args ) {
       Number[] na = new Number[100];
       Collection<Number> cn = new ArrayList<Number>();


       // This should work and does
       fromArrayToCollection( na, cn );


       Collection<String> cs = new ArrayList<String>();

       // This should fail to copile and does
       fromArrayToCollection( na, cs );
   }
}

它确实:

GenericTest1.java:25: error: method fromArrayToCollection in class GenericTest1 cannot be applied to given types;
       fromArrayToCollection( na, cs );
       ^
  required: T[],Collection<T>
  found: Number[],Collection<String>
  reason: inference variable T has incompatible bounds
    equality constraints: String
    lower bounds: Number
  where T is a type-variable:
    T extends Object declared in method <T>fromArrayToCollection(T[],Collection<T>)

但是,这可以完美地编译和运行。

public class GenericTest2 {

    // Test for equality of two objects of type T
    static <T> boolean testEquality(T first, T second ) {
        return first.equals( second );
    }


   public static void main( String[] args ) {
       // Should work
       System.out.println( testEquality( "One", "One" ) );

       // Shouldn't this refuse to compile ?
       System.out.println( testEquality( "One", 1 ) );

       // Shouldn't this refuse to compile ?
       Number one = new Integer( 1 );
       System.out.println( testEquality( "One", one ) );

   }
}

输出是:

true
false
false

任何人都可以解释原因吗?

3 个答案:

答案 0 :(得分:2)

它有效,因为oneNumber)和"One"String)都是Object1({{ 1}}由于autoboxing)和Integer"One")。因此String被评估为T,等于被调用并返回Object。 它不适用于false(及其他泛型)because a Collection<String> can not be cast to a Collection<Object>

答案 1 :(得分:1)

testEquality( "One", 1 )

作为自动装箱的结果,1此处将转换为Integer(1),这是一个对象。 String("One")Integer(1)都从.equals继承了Object函数,因此可以无误地编译。

答案 2 :(得分:0)

在第二次测试中,p=&a;只会被装入(int*)实例,该实例也是1的实例。