Question

我有一个index.html页面，用户输入他们的用户名和密码。举个例子，我有3个数据库表： 1. CLient 2.现场工作人员 3.公司。

我想要一个index.html页面，用户输入用户名和密码。他/她可以来自任何一个数据库表。现在检查用户是否来自任何一个表，我想将它们重定向到单独的页面。例如，如果用户是客户端，我想重定向到client.html。

以下是代码：

HTML

<script>
function PostData() {


    // 1. Create XHR instance - Start
    var xhr;
    if (window.XMLHttpRequest) {
        xhr = new XMLHttpRequest();
    }
    else if (window.ActiveXObject) {
        xhr = new ActiveXObject("Msxml2.XMLHTTP");
    }
    else {
        throw new Error("Ajax is not supported by this browser");
    }
    // 1. Create XHR instance - End

    // 2. Define what to do when XHR feed you the response from the server - Start
    xhr.onreadystatechange = function () {
        if (xhr.readyState === 4) {
            if (xhr.status == 200 && xhr.status < 300) {
                document.getElementById('div1').innerHTML = xhr.responseText;
            }
        }
    }
    // 2. Define what to do when XHR feed you the response from the server - Start

    var userid = document.getElementById("userid").value;
    var pid = document.getElementById("pid").value;

    // 3. Specify your action, location and Send to the server - Start 


    xhr.open('POST', 'login.php');

    xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
    xhr.send("userid=" + userid + "&pid=" + pid);
    //xhr.send("&pid=" + pid);
    // 3. Specify your action, location and Send to the server - End

}
</script>

</head>

<body>

<form>
    <label for="userid">User ID :</label><br/>
    <input type="text" name ="userid" id="userid"  /><br/>
    <label for="pid">Password :</label><br/>
    <input type="password" name="password" id="pid" /><br><br/>



    <div id="div1">
    <input type="button" value ="Login" onClick="PostData()" />
    </div>


</form>

PHP

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "db";

//session_start();
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
if(isset($_POST['userid'],$_POST['pid']))
{
  $userid = trim($_POST["userid"]);
  $pid = trim($_POST["pid"]);

  $sql = "SELECT * FROM tablename WHERE uname = '$userid' and pword = '$pid'";
  $result = mysqli_query($conn,$sql);
  $row = mysqli_fetch_array($result);

  echo "公司".'<br/>';
  echo $row['client'].'<br/>'.'<br/>';
  echo "第".'<br/>';
  echo '<a href="preview.html"/>'.$row['day1'].'</a>'.'<br/>';
?>

Answer 1

您可以使用SELECT COUNT(*) FROM tablename WHERE username = userinput检查用户是否存在。然后，您可以使用header()重定向。

Answer 2

您可能希望在数据库表上添加“字段”行以确定用户的字段 e.g。

userID |名字|年龄|字段|

a232 | meimei | 22 |客户|

然后选择'MeiMei'的用户字段，即'Client' 然后创建一个switch语句

switch ($userField) {

    case 'Client':
        // code here
        break;
    case 'Field Worker':
        // code here
        break;
    case 'Company':
        // code here
        break;
    default:
        // code to be executed if $user is different from all labels;
}

如何根据用户的输入将用户重定向到不同的网页？

2 个答案: