Question

我编写了一个通用缓存机制，我需要在结构中设置一些属性，只知道它们的reflect.Type，attribute name和reflect.Value要在属性中设置，但我不能避免类型断言，这使我的代码不通用......

func main() {
    addressNew := Address{"New Address description!"}

    // In the real problem, i know the reflect.Type of value, but
    // the struct came to me as a interface{}, just like this method
    // Return many kinds of values from redis as interface{}, 
    // (Customer, Order, Address, Product, SKU etc), in a generic way,
    // but returns the reflect.Type of value also.
    interfaceSomeValue := getMyValue()

    fmt.Printf("%v", interfaceSomeValue)
    fmt.Println("")

    // This portion of code comes from my cache mechanism, that is a library 
    // used by other projects. My cache lib really can't know all others
    // type structs to perform the type assertion, but the cache mechanism know 
    // the reflect.Type of the interface. 
    // If you try at this way, will cause a panic by try to access a FieldByName
    // in a interface, because the Customer comes from getMyValue and 
    // becomes a interface{}, and now a type assertion is 
    // required -> http://play.golang.org/p/YA8U9_KzC9
    newCustomerNewAttribute := SetAttribute(&interfaceSomeValue, "Local", interface{}(addressNew), reflect.TypeOf(Customer{}))

    fmt.Printf("%v", newCustomerNewAttribute)
    fmt.Println("")
}

func SetAttribute(object interface{}, attributeName string, attValue interface{}, objectType reflect.Type) interface{} {
    if reflect.ValueOf(object).Kind() != reflect.Ptr {
        panic("need a pointer")
    }

    value := reflect.ValueOf(object).Elem()
    field := value.FieldByName(attributeName)
    valueForAtt := reflect.ValueOf(attValue)
    field.Set(valueForAtt)
    return value.Interface()
}

Go Playground for the problem (works by hard coded type assertion)...

Go Playground for the problem (doesn't work with an unknown interface)

Answer 1

最后，我找到了一种方法。按照下面的Go Playground和代码段进行操作：

GO Playground: Avoiding Hard Coded Type Assertion

#include "stdafx.h"


int main() {
    char name;
    printf("What is your name:"); // I enter my name..
    scanf_s("%c", &name); // Should grab my name in this case (Brian)
    printf("Hello, %c\n", name); //Should print "Hello, Brian."

    return 0;
}

Go中的泛型编程。避免硬编码类型断言

1 个答案: