Question

我的数据集包含String列。如何编码基于字符串的列，就像我们在scikit-learn LabelEncoder

中所做的那样

Answer 1

我们正在开发sparkit-learn，目的是在PySpark上提供scikit-learn功能和API。您可以通过以下方式使用SparkLabelEncoder：

$ pip install sparkit-learn

>>> from splearn.preprocessing import SparkLabelEncoder
>>> from splearn import BlockRDD
>>>
>>> data = ["paris", "paris", "tokyo", "amsterdam"]
>>> y = BlockRDD(sc.parallelize(data))
>>>
>>> le = SparkLabelEncoder()
>>> le.fit(y)
>>> le.classes_
array(['amsterdam', 'paris', 'tokyo'],
      dtype='|S9')
>>>
>>> test = ["tokyo", "tokyo", "paris"]
>>> y_test = BlockRDD(sc.parallelize(test))
>>>
>>> le.transform(y_test).toarray()
array([2, 2, 1])
>>>
>>> test = [2, 2, 1]
>>> y_test = BlockRDD(sc.parallelize(test))
>>>
>>> le.inverse_transform(y_test).toarray()
array(['tokyo', 'tokyo', 'paris'],
      dtype='|S9')

Answer 2

StringIndexer就是您所需要的 https://spark.apache.org/docs/1.5.1/ml-features.html#stringindexer

from pyspark.ml.feature import StringIndexer

df = sqlContext.createDataFrame(
            [(0, "a"), (1, "b"), (2, "c"), (3, "a"), (4, "a"), (5, "c")],
            ["id", "category"]) 
indexer = StringIndexer(inputCol="category", outputCol="categoryIndex") 
indexed = indexer.fit(df).transform(df) 
indexed.show()

如何在Apache Spark中执行LabelEncoding或分类值

2 个答案: