搜索SQL数据失败

时间:2015-06-01 17:10:45

标签: php sql

我试图通过搜索查询查看来自SQL输入的数据元组,但是,结果显示了php代码的摘录。

html页面显示的结果是:

"; } } else { echo "Not Found!!!"."
"; } mysql_close(); ?> 

我需要帮助才能看出哪里出了问题。下面是SQL代码:

<html>
<head>
<title>Booking Results</title>
</head>

<BODY>
<p>&nbsp;</p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<blockquote>
  <p>
<!--  <img src='search.jpg' width=50px height=50px> //-->
  <h2>Search Booking Result</h2>
<?php 
/* connect to my sql */
$con = mysql_connect("localhost","root","password");
if (!$con)
    die('Could not connect: ' . mysql_error());
mysql_select_db("database", $con);


/* retrieve all variables  */
$keyword = @$_POST["Activity"];
$searchin = @$_POST["searchin"];


/* execute query  */
$sql="select * from sportscomplex where $searchin LIKE '%$keyword%'";
$result = mysql_query($sql);
$num=mysql_num_rows($result);

if($num != 0)
{
    while($row = mysql_fetch_array($resultActivity))
    {
        echo $row['Activity']." ".$row['Venue']." ".$row['Hall']." ".$row['Day']
             ." ".$row['Status']." ".$row['Date']."<br>";
    }
}
else
{
    echo "Not Found!!!"."<br>";
}
mysql_close();
?>

</blockquote>
</body>
</html>

0 个答案:

没有答案