Question

我正在尝试使用csv文件中的数据绘制平行坐标图。 csv文件包含四列。数据的一个例子是：

<script type="text/javascript">
$(function () {
    $.get("/mail/getmails", function (data) {
        $("#MailReceivers").selectize({
            persist: false,
            plugins: ['remove_button'],
            maxItems: null,
            valueField: 'id',
            labelField: 'name',
            searchField: ['name', 'id'],
            options: JSON.stringify(data),
            create: function (input) {
                return {name: input};
            }
        });
    });
});
</script>

我收到$dbhost = '*********'; $dbuser = '*********'; $dbpass = '*********'; $dbname = 'applicationinfo'; // Create connection $conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } // prepare and bind $stmt = $conn->prepare("INSERT INTO applicationinfo (Name, Email, Email_confirmation, Activity, Quote, Username, Password, Password_Confirmation, `13+`) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)"); // first argument can be one of 4 types (i - integer, d - double, s - string, b - BLOB) You must have one of these for each parameter/field. $stmt->bind_param("sssssssss", $name, $email, $email_conf, $activity, $quote, $username, $password, $password_conf, $one_three); // set parameters and execute $name = "Joe Snuffy"; $email = "joe.snuffy@example.com"; $email_conf = "joe.snuffy@example.com"; $activity = "Test"; $quote = "quote"; $username = "username"; $password = "password"; $password_conf = "pass conf"; $one_three = "yes"; $stmt->execute(); echo "New records created successfully"; $stmt->close(); $conn->close();的错误。我不知道我做错了什么。这是我到目前为止的代码。

A, B, C, D
1, 2, 4, 8
5, 6, 1, 5
6, 5, 5, 10

Answer 1

一种方法是为每一列创建列表，然后将其转换为数组并绘制：

例如：

A = ['1','2','3','4']     #list
A = [int(i) for i in A]
O/p A = [1,2,3,4]             #array

然后您可以绘制平行坐标。

使用CSV绘制平行坐标

1 个答案: