Question

全部帮助，

我在Informix中编写一个查询，并且一直停留在where子句中。我有2个CSQnames，我想要选择和某些时间以及所有其他我希望在另一个时间之间显示。我的查询完美运行，直到我添加了这个特定的where语句。如果有人可以提供建议我会非常感激。我收到一般错误。在Informix中，因为我无法在where子句中放入if then语句，我将如何重写语法？谢谢！

SELECT
(ccd.nodeid||"-"||ccd.sessionid||"-"||ccd.sessionseqnum) as sequenceID,
ccd.sessionid as sessionid,
ccd.sessionseqnum as sequencenum,
ccd.applicationName as AppName,
csqname as CSQName, ccd.flowout, ccd.conference,

CASE WHEN contacttype=1 THEN "Incoming" 
                WHEN contacttype=2 THEN "Outgoing"
                WHEN contacttype=3 THEN "In House"
                WHEN contacttype=4 THEN "Redirect In"
                WHEN contacttype=5 THEN "Transfer In"
END as ContactType,
CASE WHEN contactdisposition = 1 THEN "Abandoned" 
                WHEN contactdisposition = 2 THEN "Handled" 
                WHEN contactdisposition = 4 THEN "Aborted"
                WHEN contactdisposition >= 5 THEN "Rejected"
END as ContactDisposition,
CASE WHEN originatortype=1 THEN "Agent" 
                WHEN originatortype=2 THEN "Device"
                ELSE "Unknown"
END as OriginatorType,
CASE WHEN destinationtype=1 THEN "Agent" 
                WHEN destinationtype=2 THEN "Device"
                ELSE "Unknown"
END as DestinationType,
DATE(ccd.startdatetime) as date,
ccd.startdatetime as starttime,
ccd.enddatetime as endtime,
res.resourcename, ccd.transfer, ccd.redirect,
ccd.originatordn, ccd.destinationdn, 
crd.queuetime/86400 as queuetime,
acd.talktime/86400 as TalkTime, 
acd.holdtime/86400 as HoldTime, 
acd.worktime/86400 as WorkTime
FROM contactcalldetail ccd
                 Left JOIN contactroutingdetail crd ON crd.sessionID = ccd.sessionID
                 AND crd.sessionSeqNum = ccd.sessionSeqNum 
                 AND crd.nodeID = ccd.nodeID 
                 AND crd.profileID = ccd.profileID
                 LEFT JOIN agentconnectiondetail acd ON acd.sessionID = ccd.sessionID
                 AND acd.sessionSeqNum = ccd.sessionSeqNum 
                 AND acd.nodeID = ccd.nodeID 
                 AND acd.profileID = ccd.profileID
                LEFT JOIN resource res ON acd.resourceid = res.resourceid
left join contactqueuedetail cqd on cqd.sessionid=crd.sessionid
left join contactservicequeue csq on  cqd.targetid= csq.recordid

WHERE (
                ccd.startdatetime BETWEEN '2014-1-2 13:00:00' AND '2016-12-31 22:30:00'

      AND (
         if (csqname in ("CSQ_Emeriti" , "SOS-Emeriti") 

AND EXTEND(ccd.startdatetime, HOUR TO second) > DATETIME(13:30:00) HOUR TO SECOND
                 AND EXTEND(ccd.startdatetime, HOUR TO second) < DATETIME(22:00:00) HOUR TO SECOND
                                                    ) 
             or(csqname not in (“CSQ_Emeriti" , "SOS-Emeriti") 
AND 
               EXTEND(ccd.startdatetime, HOUR TO second) > DATETIME(13:00:00) HOUR TO SECOND

AND EXTEND(ccd.startdatetime, HOUR TO second) < DATETIME(22:30:00) HOUR TO SECOND
                                    )
                    )
                    AND WEEKDAY(ccd.startdatetime) BETWEEN 1 AND 5
                    AND (contacttype IN (1,4,5))
                    AND ccd.originatordn !='2155870700'
    )

Answer 1

如果查询位于 Informix ，则 SQL语句的if子句中不提供WHERE。

如果我理解你想要的是：

...
AND (
        (   
            csqname in ("CSQ_Emeriti" , "SOS-Emeriti") 
            AND EXTEND(ccd.startdatetime, HOUR TO second) > DATETIME(13:30:00) HOUR TO SECOND
            AND EXTEND(ccd.startdatetime, HOUR TO second) < DATETIME(22:00:00) HOUR TO SECOND
         ) 
    OR
        (
            csqname not in ("CSQ_Emeriti" , "SOS-Emeriti") 
            AND EXTEND(ccd.startdatetime, HOUR TO second) > DATETIME(13:00:00) HOUR TO SECOND
            AND EXTEND(ccd.startdatetime, HOUR TO second) < DATETIME(22:30:00) HOUR TO SECOND
        )
)
...

热切地问候。

Informix查询Where子句

1 个答案: