Question

我正在写一个谷歌脚本的功能，似乎我需要解决的最后一个错误是当我调用我的功能时，谷歌表中的参考不存在错误。我不知道该怎么做，因为它似乎不是我的代码的问题。有谁知道如何帮助???

感谢您的帮助！

这就是我现在的代码。它不完整，因为我需要为用户输入更改它，但这是一个测试。

在google工作表单元格中输入= sortingtesting（）

function sortingtesting() 
{
  var pInfo1 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','o','p','q','r','s']
  var pInfo2 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','o','p','q','r','s']
  var pInfo3 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','o','p','q','r','s']
  var pWO = ['1','','','2','','','3','4','5','6','7','','','8','','','9','10']
  var pSearch = ['c', 'b', 'a']

  var WO = [];
  var Info1 = [];
  var Info2 = [];
  var Info3 = [];
  var Search = [];

  for(var i = 0; i < 18; i++)
    WO[i] = pWO[i];

  for(var i = 0; i < 18; i++)
  {
      Info1[i] = pInfo1[i];
  }

  for(var i = 0; i < 18; i++)
  {
      Info2[i] = pInfo2[i];
  }

  for(var i = 0; i < 18; i++)
  {
      Info3[i] = pInfo3[i];
  }

  for(var i = 0; i < 1; i++)
    Search[i] = pSearch[i];

  // Declares secondary storage arrays and their counters
  var FinalArray1 = [];
  var FinalArray2 = [];
  var FinalArray3 = [];
  var LastArray = [];
  var a = 0;
  var b = 0;
  var c = 0;
  var d = 0;

  // loop to run and make all of the cells in the work order row relevant to the work order number
  for(var row = 0; row < WO.length; row ++)
  {
    var counter = row - 1;
    while(WO[row] == "")
    {
      WO[row] = WO[counter];
      counter--;
    }
  }

  // loop that goes through saving which work orders meet certain search criteria, each search criteria has its own separate secondary array

    for(var row = 0; row < Info1.length; row++)
    {
      if(Info1[row] == Search[0])
      {   
        FinalArray1[a] = WO[row];
        a++;
      }
    }



    for(var row = 0; row < Info1.length; row++)
    {
      if(Info2[row] == Search[1])
      {   
        FinalArray2[b] = WO[row];
        b++;
      }
    }



    for(var row = 0; row < Info1.length; row++)
    {
      if(Info3[row] == Search[2])
      {   
        FinalArray3[c] = WO[row];
        c++;
      }
    }


  // loop to run through and get all the work orders that meet all of the criteria
  for(var i = 0; i < FinalArray1.length; i++)
  {
    for(var j = 0; j < FinalArray2.length; j++)
    {
      for(var k = 0; k < FinalArray3.length; k++)
      {
        if(FinalArray3[k] == FinalArray2[j] && FinalArray2[j] == FinalArray1[i])
        {
          LastArray[d] = FinalArray1[i];
          d++;
        }
      }
    }
  }

  return LastArray;
}

发现解决方案：这是我的工作代码，数组来自Google工作表作为参数，我只是觉得将工作原型放在那里会很好：

function sortingtesting(WO, Info, Search) 
{ 
  // Declares secondary storage arrays and their counters
  var FinalArray1 = [];
  var FinalArray2 = [];
  var FinalArray3 = [];
  var LastArray = [];
  var a = 0;
  var b = 0;
  var c = 0;
  var d = 0;

  // loop to run and make all of the cells in the work order row relevant to the work order number instead of being blank
  for(var row = 0; row < WO.length; row ++)
  {
    var counter = row - 1;
    while(WO[row] == "")
    {
      WO[row] = WO[counter];
      counter--;
    }
  }

  // loop that goes through saving which work orders meet certain search criteria, each search criteria has its own separate secondary array to store the work orders that meet the criteria
  for(var col = 0; col < Info[0].length; col++)
  {
    for(var row = 0; row < Info.length; row++)
    {
      if(Info[row][col] == Search[0])
      {   
        FinalArray1[a] = WO[row];
        a++;
      }
      else if(Info[row][col] == Search[1])
      {
        FinalArray2[b] = WO[row];
        b++;
      }
      else if(Info[row][col] == Search[2])
      {
        FinalArray3[c] = WO[row];
        c++;
      }
    }
  }

  LastArray[0] = 'N/A';

  // loop to run through and get all the work orders that meet all of the criteria
  for(var i = 0; i < FinalArray1.length; i++)
  {
    for(var j = 0; j < FinalArray2.length; j++)
    {
      for(var k = 0; k < FinalArray3.length; k++)
      {
        if(FinalArray3[k] == FinalArray2[j] && FinalArray2[j] == FinalArray1[i])
        {
          LastArray[d] = FinalArray1[i];
          d++;
        }
      }
    }
  }

  return LastArray;
}

Answer 1

TL; DR该函数不应返回空数组。

通过将return "a valid string";放在脚本中的不同位置（平分代码），您将看到返回LastArray;`导致错误。

通过在调试器中运行代码，LastArray是一个空数组。

从实验中，空数组不是公式中调用的函数的有效返回值，也不是包含多个值的数组。包含一个整数的数组有效。

将var LastArray = [];更改为var LastArray = [1];就可以证明这一点。

引用不存在错误Google Script

1 个答案: