Question

我的变量未插入我的数据库中。谁能明白为什么？除了$target_file之外，所有其他字段都插入到我的表中。我是否写错了或者$_POST变量应该以不同的方式编写？

$target_dir = "images/";
$target_file = $target_dir . basename($_FILES["image1"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["image1"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["image1"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["image1"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["image1"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}

// Perform queries 
mysqli_query($con,"SELECT * FROM imgtest");
mysqli_query($con,"INSERT INTO imgtest (fname, lname, image1)VALUES ('".$_POST['fname']."', '".$_POST['lname']."', '".$_POST['$target_file']."')");

mysqli_close($con);

Answer 1

而不是

mysqli_query($con,"INSERT INTO imgtest (fname, lname, image1)VALUES ('".$_POST['fname']."', '".$_POST['lname']."', '".$_POST['$target_file']."')");

试试这个

mysqli_query($con,"INSERT INTO imgtest (fname, lname, image1)VALUES ('".$_POST['fname']."', '".$_POST['lname']."', '".$target_file."')");

Answer 2

$ target_file已经是一个变量。删除$ _POST []。

使用此

 mysqli_query($con,"INSERT INTO imgtest (fname, lname, image1)VALUES ('".$_POST['fname']."', '".$_POST['lname']."', '".$target_file."')");

在$ _POST中插入变量时，我写错了吗？

2 个答案: