TLDR;是否有一种友好的方式让Java从ROOT标准读取?反之亦然?
我有一个启动ROOT流程的Java函数。然后Java和ROOT通过stdin和stdout进行通信。好吧,无论如何,那是计划。由于某种原因,我无法通过Java进程获取cin
(ROOT)的任何信息输出。
我确信我偶然发现了几个同时发生的问题,抱歉这个长问题,所包含的代码尽可能简单
根本代码:
void test_io(){
while (true){
string in_str;
cout << "ROOT:: loop iteration";
//cout.flush(); flushing has no effect
cin >> in_str;
cout << "ROOT:: received string " << in_str;
}
}
我使用以下命令运行此代码:
root -b -q external/test_io.C
输出如下:
------------------------------------------------------------
| Welcome to ROOT 6.02/05 http://root.cern.ch |
| (c) 1995-2014, The ROOT Team |
| Built for linuxx8664gcc |
| From tag v6-02-05, 9 February 2015 |
| Try '.help', '.demo', '.license', '.credits', '.quit'/'.q' |
------------------------------------------------------------
root [0]
Processing external/test_io.C...
ROOT:: loop iteration
当我用键盘输入一些文字时,它会以明显的方式工作。
现在这里是相关的Java代码:
public void start() throws IOException{
/*
Start the process. create buffered reader and writer
*/
System.out.println("Java:: Starting Process...");
oProcess = new ProcessBuilder("root","-b","-q","external/test_io.C").start();
InputStream oIs = oProcess.getInputStream();
InputStreamReader oIsReader = new InputStreamReader(oIs);
oBr = new BufferedReader(oIsReader);
OutputStream oOs = oProcess.getOutputStream();
OutputStreamWriter oOsWriter = new OutputStreamWriter(oOs);
oBw = new BufferedWriter(oOsWriter);
}
public void communicate()throws IOException{
//sends stuff to the process and reads the results...
read_stuff();
write_stuff("message from java. blah blah blah");
read_stuff();
}
private void write_stuff(String sMessage)throws IOException{
System.out.println("Java:: write stuff: "+sMessage);
oBw.write(sMessage);
oBw.write("\n");
oBw.flush();
}
private void read_stuff()throws IOException{
/*
reads stuff from the external process. returns the last line recieved
*/
System.out.println("Java:: read_stuff...");
String sLine;
//wait for it to be ready...
long end=System.currentTimeMillis()+2000;
while ((System.currentTimeMillis() < end)){
if (oBr.ready())
break;
}
if (!oBr.ready()){
System.out.println("Java:: NOT READY :/");
return;
}
System.out.println("Java:: READY!!!");
while ((sLine = oBr.readLine()) != null) {
System.out.println("Java:: ...got line: " + sLine);
}
return;
}
调用start
然后communicate
会产生以下输出:
Java:: Starting Process...
Java:: read_stuff...
Java:: READY!!!
Java:: ...got line: ------------------------------------------------------------
Java:: ...got line: | Welcome to ROOT 6.02/05 http://root.cern.ch |
Java:: ...got line: | (c) 1995-2014, The ROOT Team |
Java:: ...got line: | Built for linuxx8664gcc |
Java:: ...got line: | From tag v6-02-05, 9 February 2015 |
Java:: ...got line: | Try '.help', '.demo', '.license', '.credits', '.quit'/'.q' |
Java:: ...got line: ------------------------------------------------------------
Java:: ...got line:
Java:: ...got line:
Java:: ...got line: Processing external/test_io.C...
然后阻止。 Java甚至没有收到'ROOT :: loop iteration'这一行。
任何帮助或指示将不胜感激。我所有的谷歌搜索和实验都是空白的。
修改
将cout
语句更改为:cout << "stuff" << endl;
使事情变得更好。我的java程序现在看起来像:
Java:: Starting Process...
Java:: read_stuff...
Java:: READY!!!
Java:: ...got line: ------------------------------------------------------------
Java:: ...got line: | Welcome to ROOT 6.02/05 http://root.cern.ch |
Java:: ...got line: | (c) 1995-2014, The ROOT Team |
Java:: ...got line: | Built for linuxx8664gcc |
Java:: ...got line: | From tag v6-02-05, 9 February 2015 |
Java:: ...got line: | Try '.help', '.demo', '.license', '.credits', '.quit'/'.q' |
Java:: ...got line: ------------------------------------------------------------
Java:: ...got line:
Java:: ...got line:
Java:: ...got line: Processing external/test_io.C...
Java:: ...got line: ROOT:: loop iteration
然后阻止。
从ROOT代码中删除行cin >> in_str;
会导致Java生成以下无限的内容:
Java:: ...got line: ROOT:: loop iteration
Java:: ...got line: ROOT:: recieved string
Java:: ...got line: ROOT:: loop iteration
...etc
所以问题现在是cin
...
答案 0 :(得分:0)
C ++输出语句没有换行符,不会刷新行。
cout << "ROOT:: loop iteration" << endl;
cin >> in_str;
cout << "ROOT:: received string " << in_str << endl;
另一个问题是,cin从来没有&#34;看到&#34;从Java程序发送的一行。你永远不会执行
System.out.println("Java:: write stuff: "+sMessage);
等
cin >> in_str;
块。
中的Java程序阻塞while ((sLine = oBr.readLine()) != null) { ... }
因为这是阻止读取。 null表示EOF,这里还没有。
您正在尝试实现一个协议,其中一方可以发送任意数量的行,但您仍然希望在Java程序中同步执行读取和写入。发送一个字符串&#34;你的回合&#34;让对方知道一堆消息已经完成是一条出路。不知道你真正想要实现什么,但