Question

我需要制作一份报告，显示各种拍卖的第二高出价者。下面列出了单次拍卖的样本数据。我如何编写一个返回的查询：

AuctionID。
第二高的出价。
最高出价和第二高出价之间的时差。

AuctionID   BidAmount   BidDate             UserID
15410       42559.23    16/11/2012 19:38    41
15410       23613.12    16/11/2012 19:16    2
15410       18000.00    16/11/2012 19:13    16
15410       15249.94    16/11/2012 18:38    9
15410       9813.50     16/11/2012 18:36    7
15410       5341.58     16/11/2012 18:16    7

Answer 1

尝试使用ROW_NUMBER功能：

DECLARE @t TABLE
    (
      AuctionID INT ,
      Amount MONEY ,
      BidDate DATETIME ,
      UserID INT
    )

INSERT  INTO @t
VALUES  ( 15410, 42559.23, '20121116 19:38', 41 ),
        ( 15410, 23613.12, '20121116 19:16', 2 ),
        ( 15410, 18000.00, '20121116 19:13', 16 ),
        ( 15410, 15249.94, '20121116 18:38', 9 ),
        ( 15410, 9813.50, '20121116 18:36', 7 ),
        ( 15410, 5341.58, '20121116 18:16', 7 );


WITH    cte
          AS ( SELECT   * ,
                        ROW_NUMBER() OVER ( PARTITION BY AuctionID ORDER BY Amount DESC ) AS rn
               FROM     @t
             )
    SELECT  c1.AuctionID ,
            c2.Amount ,
            DATEDIFF(ss, c1.BidDate, c2.BidDate) DiffInSeconds
    FROM    cte c1
            JOIN cte c2 ON c2.AuctionID = c1.AuctionID
                           AND c1.rn = 1 AND c2.rn = 2

输出：

AuctionID   Amount   DiffInSeconds
15410       23613.12 -1320

Answer 2

在MSSQL中，您可以使用以下查询选择所需的条目：

SELECT * FROM (
  SELECT
    ROW_NUMBER() OVER (ORDER BY BidAmount DESC) AS rownumber, <tablename>.*
  FROM <tablename>
)
WHERE rownumber = 2

拍卖中的第二大出价

2 个答案: