Question

我有List<object>和List<string>的记录。我希望内部加入两个列表。

以下是我的记录列表。

var listContributionDetailsToBeUpdated = new List<ContributionDetailModel> 
{
    new ContributionDetailModel { EmployeeNumber="1", EmployeeFirstName="david", EmployeeLastName="k", NHIPNumber="nhi-100" },
    new ContributionDetailModel { EmployeeNumber="2", EmployeeFirstName="xavior", EmployeeLastName="f",NHIPNumber="nhi-101"},
    new ContributionDetailModel { EmployeeNumber="3", EmployeeFirstName="george", EmployeeLastName="s", NHIPNumber="nhi-102" },
    new ContributionDetailModel { EmployeeNumber="4", EmployeeFirstName="pandit", EmployeeLastName="h",NHIPNumber="nhi-103"},
    new ContributionDetailModel { EmployeeNumber="5", EmployeeFirstName="zania", EmployeeLastName="d", NHIPNumber="nhi-104" }
};

var updatedRecored = new List<string> { "nhi-100", "nhi-101", "nhi-102" };

任何人都可以帮我加入两个列表。

Answer 1

这很直截了当。只需从贡献详细信息中选择NHIPNumber作为加入的关键：

var result = from c in listContributionDetailsToBeUpdated
             join r in updatedRecored on c.NHIPNumber equals r
             select c;

方法语法：

var result = listContributionDetailsToBeUpdated
     .Join(updatedRecored, c => c.NHIPNumber, r => r, (c, r) => c);

您也可以使用过滤而不是加入，但这不是最佳方式，因为join是一个set操作，它使用内部查找连接集合。使用简单过滤，您将具有复杂度O（N * M）而不是O（N + M）

var result = listContributionDetailsToBeUpdated
     .Where(c => updatedRecored.Contains(c.NHIPNumber));

Answer 2

以下内容也可能有效：

var result = listContributionDetailsToBeUpdated.Where(x => updatedRecored.Contains(x.NHIPNumber));

lambda表达式连接列表<object>，列表<string>

2 个答案: