Question

我正在尝试创建一个简单的文本编辑器，但我不确定如何将用户输入保存到字符串中。如何移动和控制每个字符串中的位置？另外，如何使用SI控制何时转到下一个字符串？到目前为止，我有：

matriz:

mov si, 0
mov si, offset direc    ; for directions 

mov di, 0
mov di, offset fila1    ; [si+0] for 1st row
mov word ptr[si], di
add si, 2

mov di, offset fila2    ; [si+2] for 2nd row
mov word ptr[si], di
add si, 2

mov di, offset fila3    ; [si+4] for 3rd row
mov word ptr[si], di
add si, 2

mov di, offset fila4    ; [si+6] for 4th row
mov word ptr[si], di
add si, 2

mov di, offset fila5    ; [si+8] for 5th row
mov word ptr[si], di
add si, 2

ret

...........................

write:
mov cx, 1
cycle:    
        mov ah, 2h          ; character output
        int 10h             ; display character in dl   

        mov ah, 1h          ; keyboard input
        int 21h             ; read character into al

        cmp al, 27          ; ESC
        je fin          

        cmp al, 0   
        je compararSpecialKeys

        mov byte ptr [di], al
        mov cl, dl          ; to not lose value of posX
        mov dl, al          ; to be able to print
        mov ah, 2h          ; character output
        int 10h             ; display character in dl

        mov dl, cl
        inc dl              ; to move a position
        mov posX, dl        ; update posX
        cmp posX, 38        ; border limit
        je nextline

inc di
loop cycle
jmp start

ret

nextline:
mov dl, 1
mov posX, dl    ;update posX
inc dh
mov posY, dh    ;update posY
add si, 2
call write

posX db 1 dup(1)    ; dl = posX -> controls column
posY db 1 dup(1)    ; dh = posY -> controls row
xlimit dw 38        ; number of columns
ylimit dw 24        ; number of rows    
direc db 36 dup(42) ; 42 is ASCII for space
fila1 db 36 dup(42)
fila2 db 36 dup(42)
fila3 db 36 dup(42)
fila4 db 36 dup(42)
fila5 db 36 dup(42)

Answer 1

.loop:
    mov ah, 7
    int 21h
    cmp al, 27  ; ESC
    je finish   ; that will call fin

    mov ah, 0
    int 16h     ; for special keys
    call comparar

    jmp .loop

这部分代码在循环中会做得更好，因为你想要读取多个输入，而不只是一个。此外，comparar现在在其操作的最后需要ret。

moveUp:
    mov dl, posX    ;actualizar coordinates
    mov dh, posY
    dec dh      ; posY -- 
    mov posY, dh
    jmp prntCrs     ; print cursor

我不确定这不应该是

moveUp:
    mov dl, byte [posX]    ;actualizar coordinates
    mov dh, byte [posY]
    dec dh                 ; posY -- 
    mov byte[posY], dh
    jmp prntCrs            ; print cursor

将posX和posY声明为

posX: db 0
posY: db 0

存储值。

如何使用SI和DI作为指针在汇编语言中移动matriz？

1 个答案: