Question

我尝试重置迁移时遇到问题。我正在使用oracle sql，所以当问题出现时，首先想到我已经完成了我现在在我的sqldeveloper中清空数据库我没有看到表，但如果我运行修补程序，则每个表都被创建。当我试图回滚我的迁移时，我收到一个错误，该错误引用了我在某些表中有外键的事实：外键引用的表中的唯一/主键，但是当我尝试删除约束时，artisan表示该表没有有这个约束。

以下是我的迁移文件：类别表：

public function up()
{
    Schema::create('categories', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('name');
        $table->integer('parent');
    });
    Schema::create('article_category', function(Blueprint $table){
        $table->integer('article_id')->unsigned()->index();
        $table->foreign('article_id')->references('id')->on('articles')->onDelete('cascade');
        $table->integer('category_id')->unsigned()->index();
        $table->foreign('category_id')->references('id')->on('categories')->onDelete('cascade');
        $table->timestamps();
    });
}

/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::drop('article_category');
    Schema::drop('categories');

}

文章表：

public function up()
{
    Schema::create('articles', function(Blueprint $table){

        $table->increments('id');
        $table->longText('title');
        $table->integer('user_id')->unsigned();
        $table->string('excerpt',255);
        $table->longText('body');
        $table->integer('likes')->default(0);
        $table->longText('sourceName');
        $table->longText('linkURL');
        $table->integer('views')->default(0);
        $table->timestamp('published_at');
        $table->timestamps();

        $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');

    });


}



/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::drop('articles');
}

我的角色表：

public function up()
{
    Schema::create('roles', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('name');
        $table->timestamps();
    });
    Schema::create('role_user', function(Blueprint $table){
        $table->integer('role_id')->unsigned()->index();
        $table->foreign('role_id')->references('id')->on('roles')->onDelete('cascade');
        $table->integer('user_id')->unsigned()->index();
        $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
        $table->timestamps();
    });
}

/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::drop('role_user');
    Schema::drop('roles');
}

我的代码表：

public function up()
{
    Schema::create('tags', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('name');
        $table->timestamps();
    });
    Schema::create('article_tag', function(Blueprint $table){
        $table->integer('article_id')->unsigned()->index();
        $table->foreign('article_id')->references('id')->on('articles')->onDelete('cascade');
        $table->integer('tag_id')->unsigned()->index();
        $table->foreign('tag_id')->references('id')->on('tags')->onDelete('cascade');
        $table->timestamps();
    });
}

/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::drop('article_tag');
    Schema::drop('tags');
}

所以，基本上我的数据库是空的，但我无法运行任何东西。如果我运行php artisan migrate没有创建表，但如果我运行php artisan migrate：刷新/回滚/重置表中由外键引用的表中的唯一/主键。我已经搜索了这个，但我没有找到任何适合我的问题的希望，希望我能在这里找到解决方案

Answer 1

在放桌子之前你应该dropForeign。

示例：

public function up()
{
    Schema::create('tags', function(Blueprint $table)
    {
        $table->increments('id');
        $table->string('name');
        $table->timestamps();
    });
    Schema::create('article_tag', function(Blueprint $table){
        $table->integer('article_id')->unsigned()->index();
        $table->foreign('article_id')->references('id')->on('articles')->onDelete('cascade');
        $table->integer('tag_id')->unsigned()->index();
        $table->foreign('tag_id')->references('id')->on('tags')->onDelete('cascade');
        $table->timestamps();
    });
}

/**
 * Reverse the migrations.
 *
 * @return void
 */
public function down()
{
    Schema::table('article_tag', function (Blueprint $table) {
        $table->dropForeign('article_tag_article_id_foreign');
        $table->dropForeign('article_tag_tag_id_foreign');
    });
    Schema::drop('article_tag');
    Schema::drop('tags');
}

Laravel 5外键迁移错误

1 个答案: