Question

我已经搜索了这个，但我看到的结果却恰恰相反：将多个装饰器应用于单个函数。

我想简化这种模式。有没有办法将这个单个装饰器应用于多个功能？如果没有，我怎样才能重写上述内容以减少重复？

from mock import patch

@patch('somelongmodulename.somelongmodulefunction')
def test_a(patched):
    pass  # test one behavior using the above function

@patch('somelongmodulename.somelongmodulefunction')
def test_b(patched):
    pass  # test another behavior

@patch('somelongmodulename.somelongmodulefunction')
def test_c(patched):
    pass  # test a third behavior

from mock import patch

patched_name = 'somelongmodulename.somelongmodulefunction'

@patch(patched_name)
def test_a(patched):
    pass  # test one behavior using the above function

@patch(patched_name)
def test_b(patched):
    pass  # test another behavior

@patch(patched_name)
def test_c(patched):
    pass  # test a third behavior

Answer 1

如果你想制作＆＃34; long＆＃34;函数只调用一次并用结果装饰所有三个函数，就这样做。

//node.h

struct node{
        int val;
        struct node* next;
 };

 int length(struct node *);
 struct node* push(struct node *, int);
 void print(struct node *, int);


 //node.c

 #include "./node.h"
 #include<stdlib.h>
 #include<stdio.h>

int length(struct node *current){
       if(current->next != NULL)
          return 1 + length(current->next);
       else
          return 1;
}

struct node* push(struct node *head, int num){

   struct node *temp = malloc(sizeof(struct node));
   temp->val = num;
   temp->next = head;
   head = temp;
   return head;
}

void print(struct node* head, int size){
   printf("The list is %i", size);
   printf(" long \n");
   struct node* temp;
   temp = head;
   while(temp != NULL){
   printf("%d", temp->val);
   printf(" ");
   temp = temp->next;
   }
   printf(" \n");
 }


 //main program

 #include "./node.h"
 #include<stdlib.h>
 #include<stdio.h>

  int main(){

    char ans;
    int num;
    struct node* head = NULL;

    do{
       printf("Enter a integer for linked list: ");
       scanf("%d", &num);
       head = push(head, num);
       printf("Add another integer to linked list? (y or n) ");
       scanf("%1s", &ans);
       }while(ans == 'y');

       print(head, length(head));

       return 0;
       }

Answer 2

如果您想获得幻想，可以修改globals()。下面的一般想法应该有效。

test_pattern = re.compile(r'test_\w+')
test_names = [name for name in globals().keys() if test_pattern.match(name)]
for name in test_names:
  globals()[name] = decorate(globals()[name])

将单个装饰器应用于多个功能

2 个答案: