因此，我正在制作一个刽子手游戏，用户输入一个单词，然后显示该单词，但在问号中进行伪装。每当用户正确输入单词时，该字母就会出现在问号的位置。我有猜测等所需的所有代码，我只需要有人帮助伪装用户在问号中输入的单词。
public static void main(String[] args) {
Scanner Bob = new Scanner(System.in);
ArrayList<String> alphabet = new ArrayList<String>(Arrays.asList("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"));//i looked this part up Mr. A, I didn't know how to directly set values in an arraylist
int guesses = 6;//wrong guesses
System.out.println("Hello! Please enter in your word for the game. Only one word is allowed!");
String word = Bob.next();
int lettersInWord = word.length();//so you know if you've solved the word or not
while(guesses > 0 && lettersInWord > 0){ //not or because you'll end up getting a negative 1
System.out.println("What is your guess? One letter at a time please or you'll mess up my game.");
String guess = Bob.next();
guess.toLowerCase(); //i populated the arraylist with only lowercase letters so it has to be this way
while(!alphabet.contains(guess)){ //since I remove letters from the arraylist, this is like the default to make sure a guess doesn't happen twice
System.out.println("You already guessed this letter, or this is not a letter");
guess = Bob.next();//just lets user make another guess
}
alphabet.remove(guess);//takes letter out of alphabet so no redoes happen
if(word.contains(guess)){
System.out.println("Yeauhhhhh, thats right! You guessed " + guess);
lettersInWord--;//makes the word size smaller
} else {
System.out.println("Nahhhhh, that's wrong! You guessed " + guess + " and it is not in the word");
guesses--;//takes a guess away
}
System.out.println("You have " + guesses + " wrong guesses left"); //displays at the end of the iteration
}
if(guesses == 0){//this comes up when you lose
System.out.println("You have lost, the word was "+ word);
} else {//this comes up when you've guessed the word, if its not one its the other!!!
System.out.println("You have won! the word was "+ word + "good job dude. Please see\n"
+ "Mr. A for a free piece of cake and a 100 on your final.");
}
}
答案 0 :(得分：0)
您创建一个单独的问号字符串，其长度与您的单词相同。
String marks = "";
for (int i = 0; i < word.length(); i++) {
marks += "?";
}
当正确猜到一个字母时，用字母替换一个问号。
答案 1 :(得分：0)
我最后只为你做了一个简单的例子
public class Test {
public static void main(String args[]) {
String word = "Hello";
String unCapWord = word.toLowerCase();
int guesses = word.length();
int count = 0;
char usedLetters[] = new char[26];
String testWin;
char[] guessBox = new char[word.length()];
for (int i =0; i < word.length(); i++)
guessBox[i] = '?';
Scanner bob = new Scanner(System.in);
while (count < guesses) {
char guess = bob.next().toLowerCase().charAt(0);
String checkIfCharUsed = new String(usedLetters);
if (checkIfCharUsed.contains(guess+"")) {
System.out.println("Already used this char, try another!");
continue;
}
for (int i =0; i < word.length(); i++) {
if (unCapWord.charAt(i) == guess)
guessBox[i] = guess;
}
testWin = new String(guessBox);
if (testWin.equals(unCapWord)) {
System.out.println("You got it!");
return;
}
usedLetters[count] = guess;
count++;
}
System.out.println("You lost!");
}
}
答案 2 :(得分：0)
这很快且很脏，但会在猜到的单词中显示每个字母的破折号。正如您猜测正确的字母一样，破折号将被猜到的字母替换。
public static void main(String[] args) throws Exception {
Scanner Bob = new Scanner(System.in);
ArrayList<String> alphabet = new ArrayList<>(Arrays.asList("a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"));//i looked this part up Mr. A, I didn't know how to directly set values in an arraylist
int guesses = 6;//wrong guesses
System.out.println("Hello! Please enter in your word for the game. Only one word is allowed!");
String word = Bob.next();
int lettersInWord = word.length();//so you know if you've solved the word or not
String[] lettersOfWord = new String[lettersInWord];
// Replace "-" with "?" if you want to use question marks
Arrays.fill(lettersOfWord, "-");
clearScreen();
String guess = "";
int lettersCorrect = -1;
while (guesses > 0 && lettersInWord > 0) { //not or because you'll end up getting a negative 1
if (lettersCorrect > 0) {
System.out.println(String.format("There %s %d %s",
lettersCorrect > 1 ? "are" : "is", lettersCorrect, guess));
lettersCorrect = 0;
} else if (lettersCorrect == 0) {
System.out.println("Nahhhhh, that's wrong! You guessed " + guess + " and it is not in the word");
}
System.out.println(String.join("", lettersOfWord));
System.out.println("");
System.out.println("You have " + guesses + " wrong guesses left"); //displays at the end of the iteration
System.out.println("What is your guess? One letter at a time please or you'll mess up my game.");
guess = Bob.next().toLowerCase();
while (!alphabet.contains(guess)) { //since I remove letters from the arraylist, this is like the default to make sure a guess doesn't happen twice
System.out.println("You already guessed this letter, or this is not a letter");
guess = Bob.next();//just lets user make another guess
}
alphabet.remove(guess);//takes letter out of alphabet so no redoes happen
if (word.contains(guess)) {
for (int i = 0; i < word.length(); i++) {
if (guess.equals(String.valueOf(word.charAt(i)))) {
lettersOfWord[i] = guess;
lettersInWord--;
lettersCorrect++;
}
}
} else {
guesses--;//takes a guess away
}
clearScreen();
}
if (guesses == 0) {//this comes up when you lose
System.out.println("You have lost, the word was " + word);
} else {//this comes up when you've guessed the word, if its not one its the other!!!
System.out.println("You have won! the word was " + word + " good job dude. Please see\n"
+ "Mr. A for a free piece of cake and a 100 on your final.");
}
}
// Simulate a clear screen
private static void clearScreen() {
for(int clear = 0; clear < 1000; clear++) {
System.out.println("\b") ;
}
}