我正在尝试压缩我的代码,我已经查看了一些关于连接变量的文章,但是我无法按照我需要的方式工作。
以下是两段代码。它们在功能上是相同的,除了第一个片段的变量在其名称中使用'Str'而第二个片段使用'Dex'代替。我计划使用'Int'和'Ht'创建类似的代码,但我不想复制/粘贴,然后回过头来反复更改我的代码中的'Str,Dex,Int,Ht'名称。
是否可以将'Str,Dex,Int,Ht'放入变量[var1](根据按下的按钮)然后使用[var1]代替'Str,Dex,Int,Ht'所以代码只需要写一次?
//Define Stength Increase Function
var strIncrease = function () {
//Increase playerStrength by 1
playerStr = playerStr + 1;
playerStrDisplay.innerHTML = playerStr;
//Increase strengthCP by 10
strCP = strCP + strCost;
strCPDisplay.innerHTML = strCP;
//Decrease totalCP by 10
totalCP = totalCP - strCost;
totalCPDisplay.innerHTML = totalCP;
}
//Define Dexterity Increase Function
var dexIncrease = function () {
//Increase playerDexterity by 1
playerDex = playerDex + 1;
playerDexDisplay.innerHTML = playerDex;
//Increase DexterityCP by 20
dexCP = dexCP + dexCost;
dexCPDisplay.innerHTML = dexCP;
//Decrease totalCP by 20
totalCP = totalCP - dexCost;
totalCPDisplay.innerHTML = totalCP;
}
答案 0 :(得分:4)
您可以将对象用作地图:
var player = { str: 0, dex: 0, ... };
function increase(stat) {
player[stat]++;
document.getElementById(stat + 'Display').innerHTML = player[stat];
}
increate('str');
答案 1 :(得分:0)
您可以将属性定义为对象的属性,并使用字符串访问它们,如下所示:
var player = {
str: 1,
dex: 1,
in: 1,
ht: 1,
strCP: 10,
dexCP: 10,
intCP: 10,
htCP: 10,
totalCP: 0
},
costs = {
strCost: 10,
dexCost: 10,
inCost: 10,
htCost: 10
};
function increaseAttribute(player, costs, attr) {
player[attr] += 1;
player[attr + "CP"] += costs[attr + "Cost"];
player.totalCP += costs[attr + "Cost"];
.
.
}
function increaseStr () {
increaseAttribute(player, costs, attr);
}
.
.
.
答案 2 :(得分:-1)
您可以使用closure
动态生成方法。
例如。
var player = {
str : 0
dex : 0
int : 0
ht : 0
}
function methodFactory (player, property, diff) {
var mathod = function () {
player[property] += diff;
}
return method;
}
然后
var addInt = methodFactory (player, 'int', 1);
var addIntBy2 = methodFactory (player, 'int', 2);
addInt();
写一次,到处使用