jQuery POST

Question

我发送一个带有jQuery lib的POST请求到PHP脚本，你会发现下面的脚本。我收到500内部服务器错误，有人知道如何修复它吗？

我如何发送表单：

    $.post(
        "post.php",
        $( "#form" ).serialize()
    ).done(function( data ){
            generateFinishPage( data.link );
    });

我的帖子.php

<?php
    error_reporting(E_ALL); 
    ini_set("display_errors", 1);
    $pdo = new PDO('...');

    $error = Array();

    if(empty($_POST['link']))
        $error [] = 'Er is geen link geselecteerd!';

    if(empty($_POST['sitename']))
        $error [] = 'Er is geen domein geselecteerd!';

    if(empty($_POST['image']))
        $error [] = 'Er is geen image geselecteerd!';

    $selectQuery = $pdo->query('SELECT * FROM trolls WHERE url_text="' . $_POST['url'] . '" AND url_domein="' . $_POST["sitename"] . '"');
    if($selectQuery->rowCount() == 1)
        $error [] = 'Dezelfde link bestaat al!';

    if(count($error) == 0){
        $query = $pdo->query('INSERT INTO trolls (created_time, swf_theme, url_text, url_domain, creator_ip, creator_name, creator_text, creator_email) 
            VALUES (:created_time, :swf_theme, :url_text, :url_domain, :creator_ip, :creator_name, :creator_text, :creator_email)');
        $query->execute(
            array(
                ':created_time'     =>  date('d-m-o'),
                ':swf_theme'            =>  $_POST['image'] . ".swf",
                ':url_text'             =>  explode('/', $_POST['url'])[1],
                'url_domain'            =>  explode('/', explode(".", $_POST['url'])[1])[0],
                ':creator_ip'           =>  $_SERVER['REMOTE_ADDR'],
                ':creator_name' =>  $_POST['creator_name'],
                ':creator_text'     =>  $_POST['creator_text'],
                ':creator_email'    =>  $_POST['creator_email']
            )
        );
        echo json_encode(array("link" => $_POST['url']));
    } else {
        echo json_encode(array("link" => array($error));
    }

    $pdo = null;

发送的表单数据：

  

sitename：lnstagram.nl

     

link：test

     

图像：安

     

CREATOR_NAME：测试

     

creator_email：test@test.nl

     

creator_text：测试

谢谢！

Answer 1

检查您的选择查询....是“url_domein”还是“url_domain”？

您在插入方法中尝试做什么？

我看不到任何准备好的语句但你调用了execute方法吗？

 $query->execute(
        array(
            ':created_time'     =>  date('d-m-o'),
            ':swf_theme'            =>  $_POST['image'] . ".swf",
            ':url_text'             =>  explode('/', $_POST['url'])[1],
            'url_domain'            =>  explode('/', explode(".", $_POST['url'])[1])[0],
            ':creator_ip'           =>  $_SERVER['REMOTE_ADDR'],
            ':creator_name' =>  $_POST['creator_name'],
            ':creator_text'     =>  $_POST['creator_text'],
            ':creator_email'    =>  $_POST['creator_email']
        )
    );

尝试更改此类查询...使用准备

$query = $pdo->prepare('INSERT INTO trolls (created_time, swf_theme, url_text, url_domain, creator_ip, creator_name, creator_text, creator_email) 
        VALUES (:created_time, :swf_theme, :url_text, :url_domain, :creator_ip, :creator_name, :creator_text, :creator_email)');

使用try catch block进行查询以了解错误的位置

try {
       // query here
       } catch (PDOException $pe) {
          die("Error:" . $pe->getMessage());
      }

Answer 2

直接访问你的post.php，你会发现真正的错误。并且不要忘记在yor post.php

的顶部显示错误

error_reporting(E_ALL); nullini_set('display_errors', '1');