如果是,否则代码只解析为else条件

时间:2015-05-31 17:11:11

标签: c++

我试图做一个非常基本的文字冒险来测试我的基本技能。基本运动提示用户输入,如果它匹配某些字符串,则更改其坐标。我知道,这很愚蠢。但是ifelse ifelse用于匹配其响应始终返回else,即使您输入其中一个匹配字符串也是如此。

string action;
string west = "go west";
string east = "go east";
string north = "go north";
string south = "go south";
string prompt = "Don't just stand around with your dagger in your ass! Do something! ";

//i wrote a bunch of setup story here, it's irrelevant text output

int vertical = 25;
int horizon = 20;

//action begins
start:
{
cout << "What do you do?" << endl;
cin >> action;

if (action == south)
{
    vertical = vertical - 5;
    goto descriptions;
}
else if (action == east)
{
    horizon = horizon + 5;
    goto descriptions;
}
else if (action == west)
{
    horizon = horizon - 5;
    goto descriptions;
}
else if (action == north)
{
    vertical = vertical + 5;
    goto descriptions;
}
else
{
    cout << prompt << "(Try typing \"go\" followed by a direction)" << endl;
    goto start;
}

description:
//i put a bunch of if, else if, else stuff about coordinates describing the area down here.

当我输入&#34;去东部&#34;或者&#34;去北方#34;,它打印关于匕首和驴子的提示字符串,只有在我输入其他内容时才会打印。 我究竟做错了什么?为了澄清,我在OS X 10.10.3上使用Xcode。

2 个答案:

答案 0 :(得分:7)

从输入中读取的action的值只能是"go",它会在第一个空白字符上停止。请参阅operator>>的{​​{3}}。

答案 1 :(得分:6)

cin >> string一次读一个字,而不是一行。因此,如果输入包含&#34; go north&#34;,则第一个>>将读取&#34; go&#34;而第二个&#34; north&#34;,两者都不等于&#34;去北方#34;。

使用getline阅读整行。