Question

我有这个函数返回下面的结果，但是如何删除重复的行？一个小组将会这样做但是如何将它构建到我的函数中？然后还使用＆＃39; H＆＃39;字段。

SELECT
        ACTION.holiday_id, 
        ACTION.id,
        --H.holiday_name, 
        --H.date_start,
        --H.date_end,
        (SELECT Count(DISTINCT ACTION.holiday_id) FROM ACTION) as 'Count'
FROM 
ACTION  
--INNER JOIN HOLIDAY_REF H ON ACTION.holiday_id=H.holiday_id
WHERE ACTION.delete_date is NULL
--GROUP BY ACTION.holiday_id


holiday_id id Count
31         5  3
31         6  3
31         8  3
332        7  1

所以它看起来像：

31  3

332 1

Answer 1

这应该有用。

with cte as
(
select holiday_id, 
       id, 
       holiday_name, 
       date_start, 
       date_end, 
       row_number() over (partition by holiday_id order by holiday_id) as [Index]
from Action
)
select holiday_id, id, holiday_name, date_start, date_end,
       (select count(*) from Action 
        where holiday_id = cte.holiday_id and delete_date is null) as [Count]
from cte
where [Index] = 1

编辑：同时检查delete_date

http://sqlfiddle.com/#!6/6d8ad/2

Answer 2

你有没有尝试过：

SELECT
    ACTION.holiday_id,
    Count(*) [Count] 
    FROM ACTION
WHERE ACTION.delete_date is NULL
GROUP BY ACTION.holiday_id

SQL group by在一列上选中其他列

2 个答案: