在Javascript中,我试图拆分以下字符串
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>temp</groupId>
<artifactId>TemperatureWebApp</artifactId>
<version>1</version>
<packaging>war</packaging>
<name>TemperatureWebApp</name>
<properties>
<endorsed.dir>${project.build.directory}/endorsed</endorsed.dir>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<spring.version>4.1.6.RELEASE</spring.version>
<war.outputName>TemperatureApp</war.outputName>
</properties>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.12</version>
<scope>test</scope>
</dependency>
<!-- Spring dependencies -->
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>${spring.version}</version>
<scope>compile</scope>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-web</artifactId>
<version>${spring.version}</version>
<scope>compile</scope>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>${spring.version}</version>
<scope>compile</scope>
</dependency>
<dependency>
<groupId>javax</groupId>
<artifactId>javaee-web-api</artifactId>
<version>6.0</version>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>2.3.2</version>
<configuration>
<source>1.7</source>
<target>1.7</target>
<compilerArguments>
<endorseddirs>${endorsed.dir}</endorseddirs>
</compilerArguments>
<showDeprecation>true</showDeprecation>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>2.1.1</version>
<configuration>
<outputFileNameMapping>${war.outputName}</outputFileNameMapping>
<failOnMissingWebXml>false</failOnMissingWebXml>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.1</version>
<executions>
<execution>
<phase>validate</phase>
<goals>
<goal>copy</goal>
</goals>
<configuration>
<outputDirectory>${endorsed.dir}</outputDirectory>
<silent>true</silent>
<artifactItems>
<artifactItem>
<groupId>javax</groupId>
<artifactId>javaee-endorsed-api</artifactId>
<version>6.0</version>
<type>jar</type>
</artifactItem>
</artifactItems>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
进入数组
var s1 = "(-infinity, -3],(-3,-2),[1,infinity)";
使用此声明
["(-infinity, -3]","(-3,-2)","[1,infinity)"]
解释一下,我想用逗号分隔字符串,后面用方括号或括号括起来。我使用前瞻s1.split(/(?=[\]\)]),/);
来执行此操作,但它与任何逗号都不匹配。当我将其更改为(?=[\]\)]),
时,它会匹配每个逗号。请提出我的正则表达式中的问题。
答案 0 :(得分:2)
你的逻辑是倒退的。 (?=...)
是一个前瞻性的群体,而非后视群。这意味着s1.split(/(?=[\]\)]),/);
仅在下一个字符同时为]
或)
和,
时才匹配,这是不可能的。
请改为尝试:
s1.split(/,(?=[\[\(])/);