Question

我接受xml类型的输入参数，以便我可以接受交易的保险计划列表。我需要获取xml参数并将其粉碎成一个故事变量，以便我可以处理一些逻辑。如何将XML分解为我的表变量。

这是一个用于创建包含数据的示例表的脚本;

/*
CREATE TABLE PlanData(PlanPos INT IDENTITY, PayerDX INT, PlanDX INT, PayPct DECIMAL(6,2))

INSERT PlanData(PayerDX, PlanDX, PayPct)
VALUES(10, 20, 80)
INSERT PlanData(PayerDX, PlanDX, PayPct)
VALUES(25, 50, 10)

drop table PlanData
*/

DECLARE @xmlPlans XML
SET @xmlPlans = (SELECT PlanPos, PayerDX, PlanDX, PayPct
                 FROM PlanData
                 ORDER BY PlanPos
                 FOR XML RAW('plan'), ROOT('plans')
                 )

print CAST(@xmlPlans AS NVARCHAR(max))

/* We must convert the XML passed in containing all of the insurance payer plan 
data into a usable format for the current scoping. */
DECLARE @tblPlans TABLE(PlanPos INT, IPDX INT, IPPDX INT, PayPct decimal(6, 2))   

--   /* Note that the table is built in order from Primary through the last plan */
--   INSERT @tblPlans (PlanPos, IPDX, IPPDX, PayPct)
--   SELECT x.item.value('@PlanPos[1]', 'INT') AS PlanPos,
--      x.item.VALUE('@IPDX[1]', 'INT') AS IPDX,
--      x.item.VALUE('@IPPDX[1]', 'INT') AS IPPDX,
--      x.item.VALUE('@PayPct[1]', 'decimal(6, 2)') AS PayPct
--   FROM @xmlPlans.nodes('//items/item') AS x(item)


   INSERT @tblPlans (PlanPos, IPDX, IPPDX, PayPct)
   SELECT T.plann.value('@PlanPos', 'int') AS PlanPos
      ,T.plann.VALUE('@PayerDX', 'INT') AS IPDX
      ,T.plann.VALUE('@PlanDX', 'INT') AS IPPDX
      ,T.plann.VALUE('@PayPct', 'decimal(6, 2)') AS PayPct
   FROM @xmlPlans.nodes('plans/plan') as T(plann)


---- Attribute-centered XML
--DECLARE @data XML
--SET @data = '<data><customer id="1" name="Allied Industries"/><customer id="2" name="Trades International"/></data>';
--
--DECLARE @tblCust TABLE(id INT, [name] VARCHAR(20))
--
--
---- Using the value() method
--INSERT @tblCust (id, [name])
--SELECT T.customer.value('@id', 'INT') AS customer_id,
--       T.customer.value('@name', 'VARCHAR(20)') AS customer_name
--FROM @data.nodes('data/customer') AS T(customer);   
--
--SELECT id AS dx, name AS CustName FROM @tblCust



--   SELECT x.item.value('@PlanPos[1]', 'INT') AS PlanPos,
--      x.item.VALUE('@IPDX[1]', 'INT') AS IPDX,
--      x.item.VALUE('@IPPDX[1]', 'INT') AS IPPDX,
--      x.item.VALUE('@PayPct[1]', 'decimal(6, 2)') AS PayPct
--   FROM @xmlPlans.nodes('//items/item') AS x

   SELECT
      p.PlanPos AS PlanPos,
      p.IPDX AS IPDX,
      p.IPPDX AS IPPDX,
      p.PayPct AS PayPct
   FROM @tblPlans p

你也会看到我尝试失败。

谢谢，

布赖恩

Answer 1

好的，我尝试了你的表格，我从你的FOR XML RAW.....声明中获得了以下输出：

<plans>
  <plan PlanPos="1" PayerDX="10" PlanDX="20" PayPct="80.00" />
  <plan PlanPos="2" PayerDX="25" PlanDX="50" PayPct="10.00" />
</plans>

现在要将哪些属性放入表变量的哪些列？ x.item.value(...)语句中使用的属性名称与FOR XML语句的XML结果中的实际名称不匹配。

试试这个：

DECLARE @tblPlans TABLE(PlanPos INT, IPDX INT, IPPDX INT, PayPct decimal(6, 2))   

INSERT @tblPlans (PlanPos, IPDX, IPPDX, PayPct)
  SELECT x.item.value('@PlanPos[1]', 'INT') AS PlanPos,
      x.item.value('@PayerDX[1]', 'INT') AS IPDX,
      x.item.value('@PlanDX[1]', 'INT') AS IPPDX,
      x.item.value('@PayPct[1]', 'decimal(6, 2)') AS PayPct
   FROM @xmlPlans.nodes('//plans/plan') AS x(item)

SELECT * FROM @tblPlans

我得到了这个输出：

PlanPos IPDX    IPPDX   PayPct
  1          10      20      80.00
  2          25      50      10.00

或者你真正想要的是什么？

如何将xml输入参数分解为表变量

1 个答案: